Question

What mass of AgCl is produced when 53.42 g of AgNO3 reacts with 14.19 g of NaCl?

Answer 1

Answer is: mass of silver chloride is 34,82 g.

Chemical reaction: AgNO₃ + NaCl → AgCl + NaNO₃.

m(AgNO₃) = 53,42 g..
m(NaCl) = 14,19 g.
n(AgNO₃) = m(AgNO₃) ÷ M(AgNO₃).
n(AgNO₃) = 53,42 g ÷ 169,87 g/mol.

n(AgNO₃) = 0,314 mol.

n(NaCl) = 14,19 g ÷ 58,4 g/mol.

n(NaCl) = 0,242 mol; limiting reactant.

From chemical reaction: n(NaCl) : n(AgCl) = 1 : 1.
n(AgCl) = 0,242 mol.
m(AgCl) = 0,252 mol · 143,32 g/mol.

m(AgCl) = 34,82 g.