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makvit [3.9K]
2 years ago
12

What mass of AgCl is produced when 53.42 g of AgNO3 reacts with 14.19 g of NaCl?

Chemistry
1 answer:
Leya [2.2K]2 years ago
7 0

Answer is: mass of silver chloride is 34,82 g.

Chemical reaction: AgNO₃ + NaCl → AgCl + NaNO₃.

<span>m(AgNO</span>₃) = 53,42 g..<span>
m(NaCl) = 14,19 g.
n(AgNO</span>₃) = m(AgNO₃) ÷ M(AgNO₃).<span>
n(AgNO</span>₃) = 53,42 g ÷ 169,87 g/mol.

n(AgNO₃) = 0,314 mol.

n(NaCl) = 14,19 g ÷ 58,4 g/mol.

n(NaCl) = 0,242 mol; limiting reactant.

From chemical reaction: n(NaCl) : n(AgCl) = 1 : 1.<span>
n</span>(AgCl)<span> = 0,242 mol.
m</span>(AgCl) = 0,252 mol · 143,32 g/mol.

m(AgCl) = 34,82 g.

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