Question

A ball of mass 0.190 kg has a velocity of 1.50 i m/s; a ball of mass 0.305 kg has a velocity of -0.401 i m/s.They meet in a head-on elastic collision. (a) Find their velocities after the collision.

Answer 1

Answer:

0.329m/s

Explanation:

According to law of conservation of momentum, the momentum of the object before collision is equal to that of the object after collision. Using the formula

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses of the object

u1 and u2 are the respective initial velocities

v is the final velocity

Given

m1 = 0.190kg

u1 = 1.5m/s

m2 = 0.305kg

u2 = -0.401m/s

Substitute

0.19(1.5)+(0.305)(-0.401) = (0.19+0.305)v

0.285 - 0.122305 = 0.495v

0.162695 = 0.495v

v = 0.162695 /0.495

v = 0.329m/s

Hence their velocities after collision is 0.329m/s in the positive x direction