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Rom4ik [11]
2 years ago
5

A ball of mass 0.190 kg has a velocity of 1.50 i m/s; a ball of mass 0.305 kg has a velocity of -0.401 i m/s.They meet in a head

-on elastic collision. (a) Find their velocities after the collision.
Physics
1 answer:
Mice21 [21]2 years ago
8 0

Answer:

<h3>0.329m/s</h3>

Explanation:

According to law of conservation of momentum, the momentum of the object before collision is equal to that of the object after collision. Using the formula

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses of the object

u1 and u2 are the respective initial velocities

v is the final velocity

Given

m1 = 0.190kg

u1 = 1.5m/s

m2 = 0.305kg

u2 = -0.401m/s

Substitute

0.19(1.5)+(0.305)(-0.401) = (0.19+0.305)v

0.285 - 0.122305 = 0.495v

0.162695 = 0.495v

v = 0.162695 /0.495

v = 0.329m/s

<em>Hence their velocities after collision is 0.329m/s in the positive x direction</em>

<em></em>

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Answer:

Explanation:

Hi there,

To get started, recall the kinematic equations from either a textbook, equation sheet, etc. Kinematic equations are used when acceleration is <em>constant,</em> as stated in the prompt.

Best way to use kinematic equations is to see which variable you are looking for, then which variable is unknown to you and is not needed for that equation.

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There are two equations that can be used to solve this, but we will use the less time-consuming one, but both produce same answer:

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