Answer:
a) -1.25 rev/s² and 23.3 rev
b) 2.67s
Explanation:
a) ω
= (500 rev/min)(1min/ 60s) => 8.333 rev/s
ω
= (200 rev/min)(1min/ 60s) => 3.333rev/s
time 't'= 4 s
angular acceleration 'α'=?
constant angular acceleration equation is given by,
ω= ω + αt
α= (ω - ω )/t => (3.333-8.333)/4
α= -1.25 rev/s²
θ-θ
= ω t + 1/2αt²
=(8.333)(4) + 1/2 (-1.25)(4)²
=23.3 rev
b) ω=0 (comes to rest)
ω = 3.333 rev/s
α= -1.25 rev/s²
ω= ω + αt
t= (ω - ω)/α => (0- 3.333)/-1.25
t= 2.67s
Answer:
Planetary are deflected to right due to Coriolis effect.
Explanation:
The term Coriolis effect is defined as an effect in which the rotating object experience a force called as coriolis force which acts perpendicular to the axis of rotation and direction of motion. The effect talks about how the moving objects like ocean currents, wind are deflected due to the rotation of earth.
Winds and ocean currents are strongly affect by this effect.
<span> S = k ln(W)
= 1.38*10^-23 J/K * ln(4)
= 1.91*10^-23 J/K</span>
so it will be c
Explanation:
The power P dissipated by a heater is defined as
where V is the voltage and I is the current.
a) The current running through a 130-W heater is
b) The resistance <em>R</em><em> </em>of the heater is
where 
is our familiar Ohm's Law.
Answer:
The kinetic energy of the merry-goround after 3.62 s is 544J
Explanation:
Given :
Weight w = 745 N
Radius r = 1.45 m
Force = 56.3 N
To Find:
The kinetic energy of the merry-go round after 3.62 = ?
Solution:
Step 1: Finding the Mass of merry-go-round
m = 76.02 kg
Step 2: Finding the Moment of Inertia of solid cylinder
Moment of Inertia of solid cylinder I =
Substituting the values
Moment of Inertia of solid cylinder I
=>
=> 
=> 
Step 3: Finding the Torque applied T
Torque applied T = 
Substituting the values
T = 
T = 81.635 N.m
Step 4: Finding the Angular acceleration
Angular acceleration ,
Substituting the values,
Step 4: Finding the Final angular velocity
Final angular velocity ,
Substituting the values,
Now KE (100% rotational) after 3.62s is:
KE = 
KE =
KE = 544J
