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3 years ago

15

A simple pendulum with mass m = 2.1 kg and length l = 2.32 m hangs from the ceiling. it is pulled back to an small angle of θ =

8° from the vertical and released at t = 0. 1) what is the period of oscillation?

1 answer:

Roman55 [17]3 years ago

8 0

Time period of oscillation, T = 2π Sqrt(L/g)

L = 2.32 m, g = 9.81 m/s^2

Therefore,

T = 2π*Sqrt (2.32/9.81) = 3.06 Seconds

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