Answer:
5398.4km/h
Explanation:
IN THIS CASE THE MOMENTUM IS CONSERVED. THE VALUE OF MOMENTUM OF ONE COMBINED ROCKET WILL BE SAME AS OF TWO COMBINED.
Let mass of module be m
then
mass of motor = 4m (four times the mass of rocket module)
total mass = m + 4m = 5m
combined velocity = V = 5320kph
Let
absolute (relative to earth)motor velocity after disengagement = v
then
rocket module velocity (relative to earth) after disengagement = v+98 (relative velocity = 98)
momentum conservation equation
combined momentum = module momentum + motor momentum
(m+4m)V = m(v+98) + 4m*v
5mV = 98m+mv + 4mv
5V = 98+v + 4v (m cancels out)
5V - 98 = 5v
((5*5320)-98)/5 = v
v = 5300.4 km/h
velocity of rocket module relative to earth = v +98
= 5300.4 + 98
= 5398.4km/h
Answer:
Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity.
may be it helped you
Answer:
Linear velocity of a rider in a capsule that is located at the perimeter of the wheel = 0.2355 m/s
Explanation:
Diameter = 135 m
Radius, r = 0.5 x 135 = 67.5 m
It revolves at a constant rate and takes 30 minutes
Period, T = 30 minutes= 1800 s

Linear velocity, v = radius x angular velocity
v = 67.5 x 3.98 x 10⁻³ = 0.2355 m/s
Linear velocity of a rider in a capsule that is located at the perimeter of the wheel = 0.2355 m/s
Answer:
The wavelength of the laser light is 572 nm.
Explanation:
Given that,
Distance between slit d= 0.22 mm
Distance of screen D= 0.5 m
Bright lines = 10
Width y= 1.3 cm
We need to calculate the wavelength
Using formula of young


Put the value into the formula



Hence, The wavelength of the laser light is 572 nm.