Answer:
T = 0.01 s
Explanation:
Given that,
The frequency of the beats of a hummingbird, f = 100 Hz
We need to find the period of the hummingbirds flaps. Let the time is t. We know that the relation between frequency and time period is given by :
T = 1/f
Put all the values,
T = 1/100 = 0.01 s
So, the time period of the humming bird is 0.01 s.
<span>E=hc/wav. len
E = (6.62 x 10^-34 x 3 x 10^8)/0.0275 x 10^-9
E = 7.22182 x 10^-15 J
To convert to eV divide by 1.6 x 10^-19
E = 7.22182 x 10^-15/1.6 x 10^-19 eV
E =45.36 x 10^3 eV
Th energy, E, of a single x-ray photon in eV is = 45.36keV.
Number of photons, n = total energy/ energy of photon
n = 3.85 x 10^-6/7.22182 x 10^-15
n = 5.33 x 10^8 photons </span>
Answer:
A. Tends to get shorter.
Explanation:
When a constant current is sent through a helical coil, then currents are different turns will be equal as well as in the same direction. As currents in same direction attract each other, hence coil tends to get shorter.
Answer:
The frequency increases with a shorter horn <em>(Option B)</em>.
Explanation:
The length of the horn determines the distance along which the wave travels; simply called the wavelength. Therefore, a short horn tube will produce a short wavelength and vice versa.
Sound waves have various characteristics that define pitches in musical instruments and these characteristics are interdependent on each other.
in this case, the frequency and the frequency and the wavelength are related.
The relationship between the wavelength and its frequency is given as:
<em> </em><em>c = f λ </em><em> </em>
<em>where 'c' is the speed of sound through the instrument; 'f ' is the frequency and 'λ' is the wavelength.</em>
Let's assume that the speed at which the musician blows air into the mouthpiece remains constant, an increase in wavelength will cause a decrease in frequency. Conversely, as the tube of the horn becomes shorter the frequency increases.
