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weeeeeb [17]
4 years ago
7

Which of these describes the object’s motion after the time shown on the graph?

Physics
1 answer:
DanielleElmas [232]4 years ago
7 0
There's nothing popping up
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A person uses a constant force to push a 14.0 kg crate 1.80 m up a frictionless 10⁰ incline and to also increase its speed from
zubka84 [21]

a) Making h as the shorter cathetus, we have,

h=1.8*sin10=0.312

We proceed to calculate the work done by gravity

W_g=-mgh

W_g=-140*0.312=-43.76J

b) It's necessary to calculate the Kinetic Energy, we use the equation of KE,

\Delta KE = \frac{1}{2}m(v_2^2-v_1^2)

\Delta KE = \frac{1}{2}14(1.5^2-0.5^2)=14J

c) By work energy theorem

W_{net}=\Delta KE \rightarrow W_net = 14J

d) we calculate net work through the law of conservation

W_{net}=W_f+W_g=14

\rightarrow W_f = 14-W_g=14-(-43.76)

W_f=57.76J

6 0
4 years ago
A characteristic of a substance?
GrogVix [38]

A substance could have physical characteristics and chemical ones too, which are unique to the certain substance.

Color, odor, and how hard the substance, are all examples of physical characteristics of a substance.

Toxicity, flammability, and acidity, are all examples of chemical characteristics of a substance.

8 0
3 years ago
Read 2 more answers
___ + 3H2O + light —> C3H6O3 + 3O2. What amount and substance balance this reaction?
Alik [6]

Answer:3H2O + light-c3h603+302

Explanation:

5 0
3 years ago
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⦁ A 68 kg crate is dragged across a floor by pulling on a rope attached to the crate and inclined 15° above the horizontal. (a)
GREYUIT [131]

Answer:

303.29N and 1.44m/s^2

Explanation:

Make sure to label each vector with none, mg, fk, a, FN or T

Given

Mass m = 68.0 kg

Angle θ = 15.0°

g = 9.8m/s^2

Coefficient of static friction μs = 0.50

Coefficient of kinetic friction μk =0.35

Solution

Vertically

N = mg - Fsinθ

Horizontally

Fs = F cos θ

μsN = Fcos θ

μs( mg- Fsinθ) = Fcos θ

μsmg - μsFsinθ = Fcos θ

μsmg = Fcos θ + μsFsinθ

F = μsmg/ cos θ + μs sinθ

F = 0.5×68×9.8/cos 15×0.5×sin15

F = 332.2/0.9659+0.5×0.2588

F =332.2/1.0953

F = 303.29N

Fnet = F - Fk

ma = F - μkN

a = F - μk( mg - Fsinθ)

a = 303.29 - 0.35(68.0 * 9.8- 303.29*sin15)/68.0

303.29-0.35( 666.4 - 303.29*0.2588)/68.0

303.29-0.35(666.4-78.491)/68.0

303.29-0.35(587.90)/68.0

(303.29-205.45)/68.0

97.83/68.0

a = 1.438m/s^2

a = 1.44m/s^2

7 0
4 years ago
An acrobat performs with a swing, as shown in the diagram . Which of these most likely happens as the acrobat moves from Point 1
UkoKoshka [18]
Acrobat part
A
Plants
b
Rocks
C
6 0
4 years ago
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