Answer:
23 m/s
Explanation:
The net external force on the propeller is 17N
The airplane is 0.75 kg
Therefore the acceleration of the plane can be calculated as follows
= 17/0.75
= 23 m/s
Hence the acceleration of the airplane is 23 m/s
Answer:when the two points get added.
Explanation:
Answer:
In the - j direction, that is negative of the y-axis
Explanation:
As typed in the question, the position of the object is given by the expression in three component ( i, j, k) form:
r (t) = 5 i - (t + 1 ) j + t^3 k
and since the velocity is the derivative of position with respect to time, by doing the derivative of this expression we get:
v(t) = 0 i - 1 j +3 t^2 k
which for the initial velocity requested (that is at time zero) we have:
v(t) = 0 i - 1 j +3 (0)^2 k = = 1 j
Then the direction of the initial velocity is entirely in the direction of the j versor, that is pointing to the negative of the y-axis.
Answer:
Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías
Explanation:
Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías
Answer:
The speed of the water shoot out of the hole is 20 m/s.
(d) is correct option.
Explanation:
Given that,
Height = 20 m
We need to calculate the velocity
Using formula Bernoulli equation
![\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=\dfrac{1}{2}\rho v_{2}^2+\rho gh_{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%5Crho%20v_%7B1%7D%5E2%2B%5Crho%20gh_%7B1%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Crho%20v_%7B2%7D%5E2%2B%5Crho%20gh_%7B2%7D)
Where,
v₁= initial velocity
v₂=final velocity
h₁=total height
h₂=height of the hole from the base
Put the value into the formula
![v_{1}^2=2g(h_{2}-h_{1})](https://tex.z-dn.net/?f=v_%7B1%7D%5E2%3D2g%28h_%7B2%7D-h_%7B1%7D%29)
![v_{1}=\sqrt{2g(h_{2}-h_{1})}](https://tex.z-dn.net/?f=v_%7B1%7D%3D%5Csqrt%7B2g%28h_%7B2%7D-h_%7B1%7D%29%7D)
![v_{1}=\sqrt{2\times9.8\times(20-0.005)}](https://tex.z-dn.net/?f=v_%7B1%7D%3D%5Csqrt%7B2%5Ctimes9.8%5Ctimes%2820-0.005%29%7D)
![v_{1}=19.7\ m/s= approximate\ 20\ m/s](https://tex.z-dn.net/?f=v_%7B1%7D%3D19.7%5C%20m%2Fs%3D%20approximate%5C%2020%5C%20m%2Fs)
Hence, The speed of the water shoot out of the hole is 20 m/s.