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LenKa [72]
4 years ago
15

Given the concentrations, calculate the equilibrium constant for this reaction: I2(g) +Cl2(g)⇌2ICl(g) At equilibrium, the mola

r concentrations for reactants and products are found to be [I2]=0.50 M, [Cl2]=0.60 M, and [ICl]=5.0 M. What is the equilibrium constant (Kc) for this reaction?
Chemistry
1 answer:
lawyer [7]4 years ago
6 0

Answer:

use free science lessons

Explanation:

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Can someone pls help me with this question
artcher [175]

Answer:

The answer to your question is 24.325

Explanation:

Data

Magnesium-24  Abundance = 78.70%

Magnesium-25  Abundance = 10.13%

Magnesium-26  Abundance = 11.17%

Process

1.- Convert the abundance to decimals

Magnesium-24  Abundance = 78.70/100 = 0.787

Magnesium-25  Abundance = 10.13/100 = 0.1013

Magnesium-26  Abundance = 11.17/100 = 0.1117

2.- Write an equation

Average atomic mass = (Atomic mass-1 x Abundance 1) + (Atomic mass 2 x

                                       Abundance-2) + (Atomic mass 3 x Abundance 3)

3.- Substitution

Average atomic mass = (24 x 0.787) + (25 x 0.1013) + (26 x 0.1117)

4.- Simplification

Average atomic mass = 18.888 + 2.533 + 2.904

5.- Result

Average atomic mass = 24.325

5 0
4 years ago
Mg+o2 balanced eaquation
Tanya [424]

Answer:

2Mg+O2=2MgO

balanced equation

hope it helps.

5 0
3 years ago
Read 2 more answers
What determines the types of chemical reactions that an atom participates in? A. the number of electrons in the outermost electr
Dafna1 [17]

Answer:

The answer would be A. the number of electrons in the outermost electron shell.

Explanation:

These are called valence electrons which are transferred, shared, and rearranged by creating covalent bonds producing new substances.

Hope this helped! :)

8 0
3 years ago
) Starting with 5.00 g barium chloride n hydrate yields 4.26 g of anhydrous barium chloride after heating. Determine the integer
RSB [31]

Answer:

2

Explanation:

Mass of water molecule = mass of hydrated salt - mass of anhydrous salt

Mass of water molecule = 5.00 - 4.26 = 0.74g of water molecule.

Number of moles = mass / molarmass

Molar mass of water = 18.015g/mol

No. of moles of water = 0.74 / 18.015 = 0.0411 moles.

Mass of BaCl2 present =?

1 mole of BaCl2 = 208.23 g

X mole of BaCl2 = 4.26 g

X = (4.26 * 1) / 208.23

X = 0.020

0.020 moles is present in 4.26g of BaCl2

Mole ratio between water and BaCl2 =

0.0411 / 0.020 = 2

Therefore 2 molecules of water is present the hydrated salt.

4 0
4 years ago
The vapor pressure of liquid octane, C8H18, is 40.0 mm Hg at 318 K. A sample of C8H18 is placed in a closed, evacuated container
Sergio039 [100]

Answer:

a, d

Explanation:

a. The pressure in the container will be 42.8 mm Hg.

d. Some of the vapor initially present will condense.

6 0
3 years ago
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