Describe an experiment that would allow you to determine if it is warmer inside or outside the playhouse by using two similar cu
2 answers:
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Answer:
601 nm
Explanation:
Energy of photon having wavelength of λ nm
= eV
Energy of 249 nm photon
=
=4.996 eV
Similarly energy of 425nm photon
=
=2.927 eV
Difference = 2.069 eV.
This energy will give rise to another photon whose wavelength will be
λ =
= 601 nm.