When you swing a bucket of water over your head you probably expect a
big wet rush of water to soak you as the bucket goes upside down,
However if you were swinging the bucket fast enough nothing happens.
Answer:
b. calculate the constant force exerted on the pole vaulter due to the collision
mbgiclbxhkr and you can see the pole and you are not to be a great friend of the day and night sweets is my first day of your life and my friends is my friend
To solve this problem we will apply the concept related to the electric field defined from the laws of Coulomb. For this purpose we will remember that the electric field is equivalent to the product of the Coulomb constant due to the change of the charge over the squared distance, mathematically this is

Here,
k = Coulomb's constant
r = Distance from center of terminal to point where electric field is to found
q = Excess charge placed on the center of terminal of Van de Graff's generator
Replacing we have that,


Therefore the electric field is 
Let x = the angle of elevation for shooting the arrow.
Assume
g = 9.8 m/s²
No wind resistance
The vertical launch velocity is 25.1 sin(x) m/s
The horizontal velocity is 25.1 cos(x) m/s
The time of flight is
24/[25.1 cos(x)] s = 0.9562 sec(x) s
Therefore
0.5*[0.9562 sec(x)]*(9.8) = 25.1 sin(x)
4.6854 = 25.1* sin(x)cos(x)
sin(2x) = 0.3733
2x = sin⁻¹ 0.3733 = 21.92 deg
x = 10.96 deg
Answer: 11 degrees (nearest integer)