It doesn’t, a new tooth underneath your old one starts to push the right old one out, then the tooth comes loose and the tooth underneath continues growing.
Hope my answer helps!
Yes it does. But not always
We can solve the problem by using the mirror equation:

where
f is the focal length

is the distance of the object from the mirror

is the distance of the image from the mirror
For the sign convention, the focal length is taken as negative for a convex mirror:

and the image is behind the mirror, so virtual, therefore its sign is negative as well:

putting the numbers in the mirror equation, we find the distance of the object from the mirror surface:

So, the distance of the object from the mirror is
Since you are looking at a right fringe, the answer is all
the time a multiple of the wavelength for the reason that the light makes
constructive intrusion. If you are looking at the center (zeroth) fringe, the
difference is (450)(0) = 0. For the first maximum, the difference is 450 nm.
For the second, it is 450 x 2 = 900 nm. Basically, for the nth maxima, the
difference is 450n.
False. It does repeat itself