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Bumek [7]
3 years ago
10

Which of the following is an exercise myth?

Physics
2 answers:
Margaret [11]3 years ago
8 0
The answere is No pain, no gain
Masja [62]3 years ago
3 0

No Pain, No Gain!!!!

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Would this one be correct?(C.)
BaLLatris [955]
No. The correct one would be D .
5 0
3 years ago
What is the least force you could exert on the refrigerator to move it?
Ulleksa [173]
 <span>If the refrigerator weights 1365 and you are not exerting any vertical force on it, then the normal force is also 1365N. so Fn=1365 

Fsf = Static frictional force = (coefficient of static friction) * (Normal force) 

So the least for you could exert to move it is equal to the Fsf. 
Fsf = (0.49)(1365N)</span><span>
</span>
8 0
3 years ago
The gravitational force experienced by Earth due to the Moon is ________ the gravitational force experienced by the Moon due to
Vsevolod [243]

The gravitational force experienced by Earth due to the Moon is <u>equal to </u>the gravitational force experienced by the Moon due to Earth.

<u>Explanation</u>:

The force that attracts any two objects/bodies with mass towards each other is defined as gravitational force. Generally the gravitational force is attractive, as it always pulls the masses together and never pushes them apart.

The gravitational force can be calculated effectively using the following formula: F=GMmr^2  

where “G” is the gravitational constant.

Though gravity has the ability to pull the masses together, it is the weakest force in the nature.

The mass of the Earth and moon varies, but still the gravitational force felt by the Earth and Moon are alike.

5 0
3 years ago
What is the definition magnitude?
strojnjashka [21]

Answer:

What is the definition magnitude?

Magnitude (mathematics), a measure of the size of a mathematical object.

xXxAnimexXx

Have a great day!

4 0
2 years ago
Read 2 more answers
Find the minimum kinetic energy in MeV necessary for an α particle to touch a 39 19 K nucleus that is initially at rest, assumin
SIZIF [17.4K]

Answer:

KE = 9.6MeV

Explanation:

Given the relationships we understand that,

q_1 = 19e, q_2 = 2e

The Potential at point p, is given by the following formula

V_ {p} = \frac {Kq_1} {r}

According to the graphic designed, you have,

V_ {p} = \frac {Kq_1} {(r_1 + r_2)}

V_ {p} = \frac {(9 * 10 ^ 9) (19 * 1.6 * 10 ^ {- 15})} {(3.7 + 2) * 10 ^{- 15}}}

V_ {p} = 4.8 * 10 ^ 6V

The kinetic energy of the particle would be given by

KE = q_2 * V_ {p} = 2e * 4.8 * 10 ^ 6V

KE = 9.6MeV

4 0
3 years ago
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