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Bumek [7]
4 years ago
10

Which of the following is an exercise myth?

Physics
2 answers:
Margaret [11]4 years ago
8 0
The answere is No pain, no gain
Masja [62]4 years ago
3 0

No Pain, No Gain!!!!

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AlexFokin [52]
A) as a longitudinal wave
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3 years ago
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, wha
anygoal [31]
<span>F = m*a = 7000kg * 9.8N/kg = 68,600 N. 

68,600 N is your answer
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3 years ago
Wind blows at the speed of 30m/s across a 175m^2 flat roof if a house.
Makovka662 [10]

Answer:

the net force is 101587.5 N

Explanation:

The speed of wind

v = 30 m/s

The area of roof,

A = 175 m 2

The expression for the Bernoulli's theorem.

P = 12 ρv 2 ...... (1)

Here,

P is the pressure difference,

ρ is the density of air and

v is the speed of wind.

The expression for the pressure.

P = F A ..... (2)

Here,

F is the force and

A is the area of roof.

Part (a)

Substitute the values for the pressure difference in equation (1)

P = 12 × 1.29 × (30) 2 P = 580.5 Pa

Thus, the pressure difference at the roof between the inside and outside air is

580.5 Pa

Part (b)

Substitute the values for the net force in equation (2)

580.5 = F 175 F = 101587.5 N

Thus, the net force is 101587.5 N.

8 0
4 years ago
If you have a pet that isn't getting nourishment from the food it eats, which organ might
tatuchka [14]
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4 0
4 years ago
If you install special sound-reflecting windows that reduce the sound intensity level by 30.0 db , by what factor have you reduc
shusha [124]

Answer: The sound intensity was reduced by -14.77 dB.

Explanation:

The level of the intensity of the sound with respect to the reference value is called Sound Intensity level.

L_I=10\log\frac{I}{I_o} dB

I = Intensity of the sound

I_o = Reference sound intensity

According to question, sound-reflecting windows that reduce the sound intensity level by 30.0 db .

Let the intensity of the sound be I_o and reduced intensity be I.

I=\frac{I_o}{30} dB

L_I=10\log\frac{I}{I_o} dB

L_I=10\log\frac{\frac{I_o}{30}}{I_o}=10\log\frac{1}{30} dB=-14.77 dB

The sound intensity was reduced by -14.77 dB.

3 0
3 years ago
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