Answer: 0.225 atm
Explanation:
For this problem, we have to use Boyle's Law.
Boyle's Law: P₁V₁=P₂V₂
Since we are asked to find P₂, let's manipulate the equation.
P₂=(P₁V₁)/V₂

With this equation, the liters cancel out and we will be left with atm.
P₂=0.225 atm
Answer:
9.55 grams of SiO2
Explanation:
If the mass you mean by grams:
0.159 mole x 60.08 g (Periodic table by adding both elements)
Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:
9.55 grams of SiO2
The molar mass of NH4NO3 in g/mol is 80g/mol.
HOW TO CALCULATE MOLAR MASS:
The molar mass of a compound can be calculated by summing the atomic masses of its constituent elements.
In ammonium nitrate (NH4NO3), there are nitrogen, hydrogen, and oxygen elements.
- Atomic mass of nitrogen = 14
- Atomic mass of oxygen = 16
- Atomic mass of hydrogen = 1
Molar mass of NH4NO3 = 14 + 1(4) + 14 + 16(3)
Molar mass of NH4NO3 = 80g/mol
- Therefore, the molar mass of NH4NO3 in g/mol is 80g/mol.
Learn more about molar mass at: brainly.com/question/8101390?referrer=searchResults
Answer:
Part A is just T2 = 58.3 K
Part B ∆U = 10967.6 x C
You can work out C
Part C
Part D
Part E
Part F
Explanation:
P = n (RT/V)
V = (nR/P) T
P1V1 = P2V2
P1/T1 = P2/T2
V1/T1 = V2/T2
P = Pressure(atm)
n = Moles
T = Temperature(K)
V = Volume(L)
R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.
bar = 0.986923 atm
N = 14g/mol
N2 Molar Mass 28g
n = 3.5 mol N2
T1 = 350K
P1 = 1.5 bar = 1.4803845 atm
P2 = 0.25 bar = 0.24673075 atm
Heat Capacity at Constant Volume
Q = nCVΔT
Polyatomic gas: CV = 3R
P = n (RT/V)
0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))
V = (nR/P) T
V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K
V = (0.28721/1.4803845) x 350
V = 0.194 x 350
V = 67.9036 L
So V1 = 67.9036 L
P1V1 = P2V2
1.4803845 atm x 67.9036 L = 0.24673075 x V2
100.52343693 = 0.24673075 x V2
V2 = P1V1/P2
V2 = 100.52343693/0.24673075
V2 = 407.4216 L
P1/T1 = P2/T2
1.4803845 atm / 350 K = 0.24673075 atm / T2
0.00422967 = 0.24673075 /T2
T2 = 0.24673075/0.00422967
T2 = 58.3 K
∆U= nC
∆T
Polyatomic gas: C
= 3R
∆U= nC
∆T
∆U= 28g x C
x (350K - 58.3K)
∆U = 28C
x 291.7
∆U = 10967.6 x C