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Alex
2 years ago
12

PLEASE HELP WILL MARK BRAINLIEST

Physics
1 answer:
BabaBlast [244]2 years ago
3 0

Answer:

I think it is law of inertia or Newton first law

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A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 m above the ground as he rele
kirill115 [55]

Explanation:

It is given that,

Speed of the ball, v = 10 m/s

Initial position of ball above ground, h = 20 m

(a) Let H is the maximum height reached by the ball. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh'            

h'=\dfrac{v^2}{2g}

h'=\dfrac{(10)^2}{2\times 9.8}

h' = 5.1 m

The maximum height above ground,

H = 5.1 + 20

H = 25.1 meters

So, the maximum height reached by the ball is 25.1 meters.

(b) The ball's speed as it passes the window on its way down is same as the initial speed i.e. 10 m/s.

Hence, this is the required solution.                              

6 0
3 years ago
Which statement best describes the difference between a substance with a pH of 3.0 and a substance with a pH of 6.0?
satela [25.4K]

The statement best describes the difference between a substance with a pH of 3.0 and a substance with a pH of 6.0 is - The substance with the lower pH has 1,000 times as many hydrogen ions per volume of water.

pH is the scale or measure for the substance about its acidic or basic strength. It ranges from 0 to 6.9 which is acidic and 7.1 to 14 which is basic.

Acidic substance has high concentration of Hydrogen ions whereas, basic substance has low concentration of hydrogen ions, however for the OH⁻ ions it is reverse.

  • Concentration of hydrogen ions is inversely related to its pH
  • More hydrogen ions present, the lower the pH
  • The fewer hydrogen ions, the higher the pH We know,

pH = -log(H^{+}) then,  

=> 3 = -log (H^{+})

=> H^{+} =  (for pH = 3)  

=> pH = -log(H^{+})

=> 6 = -log (H^{+})

=> H^{+} = 10^{-6} (for pH = 6)

 Thus, The substance with the lower pH (3) has 1000 times as many hydrogen ions per volume of water.

Learn more about pH scale:

brainly.com/question/1596421

7 0
3 years ago
An 80 g, 40 cm long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 15 g ball of clay trav
fiasKO [112]

Answer:

θ  = 12.95º

Explanation:

For this exercise it is best to separate the process into two parts, one where they collide and another where the system moves altar the maximum height

Let's start by finding the speed of the bar plus clay ball system, using amount of momentum

The mass of the bar (M = 0.080 kg) and the mass of the clay ball (m = 0.015 kg) with speed (v₀ = 2.0 m / s)

Initial before the crash

      p₀ = m v₀

Final after the crash before starting the movement

     p_{f} = (m + M) v

     p₀ = p_{f}

     m v₀ = (m + M) v

     v = v₀ m / (m + M)

     v = 2.0 0.015 / (0.015 +0.080)

     v = 0.316 m / s

With this speed the clay plus bar system comes out, let's use the concept of conservation of mechanical energy

Lower

    Em₀ = K = ½ (m + M) v²

Higher

    E_{mf} = U = (m + M) g y

   Em₀ = E_{mf}

   ½ (m + M) v² = (m + M) g y

   y = ½ v² / g

   y = ½ 0.316² / 9.8

   y = 0.00509 m

Let's look for the angle the height from the pivot point is

    L = 0.40 / 2 = 0.20 cm

The distance that went up is

     y = L - L cos θ

     cos θ  = (L-y) / L

     θ  = cos⁻¹ (L-y) / L

     θ  = cos⁻¹-1 ((0.20 - 0.00509) /0.20)

      θ  = 12.95º

4 0
3 years ago
Plz help me asap !!!!!!!!!!
nlexa [21]

Answer:

B- 65km

C- 2.8km/h

D- average speed

6 0
3 years ago
A cannonball is fired vertically upwards at 100.0 m/s a) How long will it take to return to the cannon? b) what is it's maximum
V125BC [204]
Answer:
a) 20s
b) 500m

Explanation:
Given the initial velocity = 100 m/s, acceleration = -10m/s^2 (since it is moving up, acceleration is negative), and at the maximum height, the ball is not moving so final velocity = 0 m/s.

To find time, we apply the UARM formula:

v final = (a x t) + v initial

Replacing the values gives us:

0 = (-10 x t) + 100

-100 = -10t

t = 10s

It takes 10s for the the ball to reach its max height, but it must also go down so it takes 2 trips, once going up and then another one going down, both of which take the same time to occur

So 10s going up and another 10s going down:

10x2 = 20s

b) Now that we have v final = 0, v initial = 100, a = -10, t = 10s (10s because maximum displacement means the displacement from the ground to the max height) we can easily find the displacement by applying the second formula of UARM:

Δy = (1/2)(a)(t^2) + (v initial)(t)

Replacing the values gives us:

Δy = (1/2)(-10)(10^2) + (100)(10)

= (-5)(100) + 1000

= -500 + 1000

= 500 m

Hope this helps, brainliest would be appreciated :)
7 0
2 years ago
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