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3 years ago

X(HCO3)2 Express your answer as a whole number.

Chemistry

1 answer:

emmainna [20.7K]3 years ago

5 0

Wym? Idk how to use this app will you help me? Is it possible orrrrrrr

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If the only chemical you can find is labeled with the wrong concentration:_______

Softa [21]

Answer:inform the lab instructor and get instructions

Explanation:

If you come across a chemical in the laboratory which has been wrongly labelled, do not be quick to dilute it or take any further action. The laboratory instructor who may have prepared the reagent himself or has better knowledge about the reagent should be contacted immediately so that he/she can give you instructions about what to do with the wrongly labelled reagent.

3 0

4 years ago

The decomposition of nitrogen dioxide to nitrogen monoxide and oxygen gas is a second order process as suspected in the previous

lesya [120]

Explanation:

For the given reaction $2NO_{2} \rightarrow 2NO + O_{2}$

Now, expression for half-life of a second order reaction is as follows.

$t_{1/2} = \frac{1}{[A_{0}]k}$ ....... (1)

Second half life of this reaction will be $t_{1/4}$ . So, expression for this will be as follows.

$t_{1/4}$ = $\frac{1}{k} [\frac{1}{[A]_{f}} - \frac{1}{[A_{0}]}]$ ...(2)

where $[A]_{f}$ is the final concentration that is, $\frac{[A]_{0}}{4}$ here and $[A]_{i}$ is the initial concentration.

Hence, putting these values into equation (2) formula as follows.

$t_{1/4}$ = $\frac{1}{k} [\frac{4}{[A]_{0}} - \frac{1}{[A_{0}]}]$

= $\frac{3}{[A_{0}]k}$ ...... (3)

Now, dividing equation (3) by equation (1) as follows.

$\frac{t_{1/4}}{t_{1/2}}$ = $\frac{3}{[A_{0}]k} \times [A_{0}]k$

= 3

or, $t_{1/4}$ = 3 $t_{1/2}$

Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.

6 0

3 years ago

Ammonia is a gas for which reliable analytical methods are available to determine its concentration in other gases. To measure f

IgorLugansk [536]

amount of ammonia injected:

72.3 kg/min x 12 min = 867.6 kg

ammonia concentration = 0.382%

$\tt 0.382\%=\dfrac{mass~amonia}{mass~ammonia+mass~natural~gas}\times 100\%\\\\0.00382=\dfrac{867.6}{867.6+mass~natural~gas}\\\\mass~natural~gas=226,252.88~kg/12min=1131264.4~kg/h$

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2 years ago

Which compound(s) contain the most hydrogen atoms per molecule or formula unit? hydrogen selenide ammonium bromide strontium dih

igomit [66]

The answer is strontium dihydrogen phosphate

That is strontium dihydrogen phosphate, is the compound containing the most hydrogen atoms per molecule or formula unit.

The formulas of the following compounds are as follows:

Hydrogen selenide H₂Se

Ammonium bromide NH₃Br

Strontium dihydrogen phosphate Sr(H₂PO4)₂

Sodium bicarbonate NaHCO₃

As it can be seen from the formula of strontium dihydrogen phosphate Sr(H₂PO4)₂ , that it contains the most hydrogen atoms per molecule or formula unit.

3 0

3 years ago

Why should we work to protect estuaries? Select all that apply.<br> PLSSSS

True [87]

Answer:

1, 3, and 4

Explanation:

I'm guessing, but those make the most sense

8 0

3 years ago

Read 2 more answers