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Vlad [161]
3 years ago
5

How would i solve for force when there are multiple accelerations?

Physics
1 answer:
damaskus [11]3 years ago
8 0

"Multiple accelerations" is a puzzling phrase, and I'd be curious to understand it
better.  Sadly however, you haven't explained it at all.

If the multiple accelerations are the accelerations of multiple objects, then
the net force on each object is the product of (its mass) x (its acceleration).

If the multiple accelerations are the acceleration of one object at different times,
then at any instant of time, the net force on the object is the product of (its mass) x
(its acceleration at that instant).

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A car travels at a constant speed up a ramp making an angle of 28 degrees with the horizontal component of velocity is 40 kmh^-1
Hoochie [10]

Answer:

Vx = 35.31 [km/h]

Vy = 18.77 [km/h]

Explanation:

In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.

v_{x} = 40*cos(28)\\V_{x} = 35.31 [km/h]

In order to find the vertical component, we must use the sine function of the angle.

V_{y}=40*sin(28)\\V_{y} = 18.77 [km/h]

7 0
3 years ago
Marine science- question- what is climate change?
Troyanec [42]

Answer:

Defined below

Explanation:

Climate change is simply the long term change in the average weather patterns that are associated with the local, regional and global climates of the earth. Climate change is usually driven by human activities like burning of fossils; natural processes like cyclic ocean patterns; external factors like volcanic eruptions.

8 0
3 years ago
A research submarine can withstand an external pressure of 62 megapascals (million pascals) all the while maintaining a comforta
Alex

Answer:

<em>The depth will be equal to</em> <em>6141.96 m</em>

<em></em>

Explanation:

pressure on the submarine P_{sea} = 62 MPa = 62 x 10^6 Pa

we also know that P_{sea} = ρgh

where

ρ is the density of sea water = 1029 kg/m^3

g is acceleration due to gravity = 9.81 m/s^2

h is the depth below the water that this pressure acts

substituting values, we have

P_{sea} = 1029 x 9.81 x h = 10094.49h

The gauge pressure within the submarine P_{g} = 101 kPa =  101000 Pa

this gauge pressure is balanced by the atmospheric pressure (proportional to 101325 Pa) that acts on the surface of the sea, so it cancels out.

Equating the pressure P_{sea}, we have

62 x 10^6 = 10094.49h

depth h = <em>6141.96 m</em>

7 0
3 years ago
Please help i’ll mark you
suter [353]

Answer:

What should I do. reply quickly for a quick answer

8 0
2 years ago
Read 2 more answers
Coulomb is the unit of which quantity?
zmey [24]

Answer:

electric charge

4 0
3 years ago
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