Answer:
31.9 mi
Step-by-step explanation:
AC/sin(angleABC) = AB/sin(angleACB)
Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is given by:

In this problem, we have that:

99.5% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So







A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
4x-5=31
Add 5 to both sides
4x=36
Divide both sides by 4
x=9
Final answer: 9
<span>z^2-z(z+3)+3z
z^2 - z^2 - 3z + 3z
0 + 0
0
</span><span>z^2-z(z+3)+3z = 0</span>
50.1 repeateding because that is the only positive number