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3 years ago

12

Someone help me solve this I need to know how to do it

1 answer:

Reil [10]3 years ago

4 0

I'm gonna say that the answer if 12 (correct me if i'm wrong) so basically, following order of operations, you weed need to subtract something first, before that though, you need to find what number you can multiply 4 with to get 12, which the answer is 3. Knowing this, you need the subtraction problem to equal 3, so you add 3+2=5. x=5. so to put it in perspective, 5-2=3x4=12 hopefully i explained this well

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3 years ago

Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children

Shkiper50 [21]

Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

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In this problem, we have that:

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99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}$

$0.07\sqrt{n} = 1.2996$

$\sqrt{n} = \frac{1.2996}{0.07}$

$\sqrt{n} = 18.5658$

$(\sqrt{n})^{2} = (18.5658)^{2}$

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A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

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3 years ago

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g100num [7]

4x-5=31

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Divide both sides by 4
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