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3 years ago

How to use proton, neutron, and isotope in a sentence

2 answers:

8 0

An isotope of an element contains the same number of protons as the original element however, the number of neutrons depends on the different isotopes of the element.

Natalka [10]3 years ago

7 0

An isotope of an element contains the same number of protons and electrons, but different number of neutrons.

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A 20 watt light bulb is left burning inside a refrigerator operating on a reverse Carnot cycle. If the refrigerator also draws 2

Gwar [14]

Explanation:

Given that,

Power drawn by the refrigerator = 20 watt

Power of burning light inside = 20 watt

Room temperature = 27°C

We need to calculate the temperature

Using formula of coefficient of refrigerator

$COR_{R}=\dfrac{Q_{c}}{W}$

$\dfrac{Q_{c}}{W}=\dfrac{T_{c}}{T_{H}-T_{c}}$

Put the value into the formula

$\dfrac{20}{20}=\dfrac{T_{c}}{T_{H}-T_{c}}$

$\dfrac{T_{c}}{T_{H}-T_{c}}=1$

$T_{h}=2T_{c}$

$T_{c}=\dfrac{T_{h}}{2}$

$T_{c}=\dfrac{27+273}{2}$

$T_{c}=150\ K$

$T_{c}$ is less than $T_{h}$

Therefore, refrigerator cools its interior below room temperature while the bulb is on.

Hence, This is the required solution.

8 0

4 years ago

what is the momentum of a 10000kg truck whose velocity is 20m/s and what velocity must a 5000kg truck attain in order to have th

Mice21 [21]

Answer:

40m/s

Explanation:

P=mv

m1v1=m2v2

(20)(10000)=(5000)v

200000=5000(v)

v=40m/s

4 0

4 years ago

Read 2 more answers

If a wave has a speed of 362 m/s and a period of 4.17 ms, its wavelength is closest to

Dominik [7]

Answer:

Option A (1.51 m) is the appropriate option.

Explanation:

The given values are:

Speed of wave,

= 362 m/s

Period,

= 4.17

Now,

⇒ $v=\frac{\lambda}{T}$

then,

⇒ $\lambda=vT$

⇒ $= 362\times 4.17\times 10^{-3}$

⇒ $=1.51 \ m$

3 0

3 years ago

5. A 5.0 kg object accelerates uniformly from rest for 5.0 s and reaches a final velocity of 20.0 m/s. At 3.0 s, what is the obj

irina [24]

Answer:

jack JACKKK

Explanation:

OK YAHHHHH SO DO THIS

3 0

4 years ago

An electron de-excites from the fourth quantum level to the third and then directly to the first. Two frequencies of light are e

4vir4ik [10]

Answer:

The answer is explained below.

Explanation:

The energy emitted during the de-excitation of an electron from a higher energy level to a lower energy level is directly proportional to the frequency of the emitted light.

Here, the total sum of the energies of 2 frequencies of light emitted in different stages is equal to the energy of a single frequency of light during the de-excitation of fourth level to ground level directly.

Hence the total sum of of the frequencies of 2 lights emitted in different stages is equal to the frequency of single frequency of light emitted during the de-excitation from fourth level to ground level directly.

The some of the energies of 2 frequencies emitted by one electron is equal to the energy of a single frequency when electron jumps directly.

6 0

3 years ago