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3 years ago

How to use proton, neutron, and isotope in a sentence

2 answers:

8 0

An isotope of an element contains the same number of protons as the original element however, the number of neutrons depends on the different isotopes of the element.

Natalka [10]3 years ago

7 0

An isotope of an element contains the same number of protons and electrons, but different number of neutrons.

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Red light has a wavelength of 500 nm. What is the frequency of red light?

snow_tiger [21]

Answer:

$0.6 \times 10 {}^{15}$

Explanation:

By using relation,

Speed of light = frequency × wavelength (in m)

3 0

3 years ago

A right triangle has sides measuring 5 and 12 inches. If the two vectors have a magnitude of 5 and 12 and are at right angles to

ollegr [7]

Answer:

$x=13$

Explanation:

From the question we are told that

Magnitude 1 $M_1=5$

Magnitude 1 $M_2=12$

Generally the Pythagoras equation for the magnitudes is mathematically given as

$\sqrt{x^2}=\sqrt{M_1^2 +M_2^2}$

$\sqrt{x^2}=\sqrt{5^2 +12^2}$

$x=13$

Therefore resultant magnitude is

$x=13$

8 0

3 years ago

how do you Compute the approximate acceleration of gravity for an object above the earth's surface, assigning accel gravity with

solong [7]

The approximate acceleration of gravity for an object above the earth's surface is 9.8 m/s².

<h3>Acceleration due to gravity </h3>

The acceleration due to gravity of an object above the Earth's surface is calculated from Newton's second law of motion and Newton's law of universal gravitation.

<h3>Force between the object and Earth</h3>

$F_g = \frac{GmM}{R^2}$

<h3>Weight of the object</h3>

$F_g = mg\\$

Solve (1) and (2)

mg = GmM/R²

g = GM/R²

where;

M is mass of Earth
G is gravitational constant
R is radius of the Earth = 6,371 km

g = (6.673 x 10⁻¹¹ x 5.98 x 10²⁴)/(6,371 x 10³)²

g = 9.8 m/s²

Learn more about acceleration due to gravity here: brainly.com/question/88039

#SPJ1

7 0

2 years ago

Two wires are parallel and one is directly above the other. Each has a length of 50.0 m and a mass per unit length of 0.020 kg/m

ivann1987 [24]

Answer: The time required for the impluse passing through each other is approximately 0.18seconds

Explanation:

Given:

Length,L = 50m

M/L = 0.020kg/m

FA = 5.7×10^2N

FB = 2.5×10^2N

The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.

Ca(t) + CB(t) = 50

Where CA and CB are the velocities of the wire A and B

t = 50/ (CA + CB)

But C = Sqrt(FL/M)

Substituting gives:

t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))

t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))

t = 50 / (168.62 + 111.83)

t = 50/280.15

t = 0.18 seconds

4 0

3 years ago

Read 2 more answers

Answered: A 4 kg mass is attached to a horizontal spring with the spring constant of 600 N/m and rests on a frictionless surface

butalik [34]

Glad it’s figured out

6 0

3 years ago