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3 years ago

Which waves cause the medium to vibrate only in a direction parrallel?

2 answers:

6 0

Transverse, longitudinal, & surface waves. Which wave causes the medium to vibrate only in a direction parallel to the wave's motion?

34kurt3 years ago

4 0

A longitudinal wave is a mechanical wave that causes the medium to vibrate parallel to the direction of the wave. Its wave’s forces travel through multiple rarefactions and compressions where compression is the closest distance in the longitudinal wave and rarefaction is the farthest distance apart in the said wave.

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A 2.5 kg cat is resting on top of a bookshelf that is 3 meters high. What is the cats gravitational potential energy relative to

erma4kov [3.2K]

Answer:

The answer to your question is Ep = 73.6 Joules

Explanation:

Data

mass = 2.5 kg

height = 3 m

gravity = 9,81 m/s²

Potential energy = ?

Potential energy is the energy stored in an object due to its position, the highest the object be, the highest the potential energy.

Formula

Pe = mgh

Substitution

Ep = (2.5)(9.81)(3)

Simplification and result

Ep = 73.6 Joules

4 0

3 years ago

One recently discovered extrasolar planet, or exoplanet, orbits a star whose mass is 0.70 times the mass of our sun. This planet

Stels [109]

0.078 times the orbital radius r of the earth around our sun is the exoplanet's orbital radius around its sun.

Answer: Option B

Explanation:

Given that planet is revolving around the earth so from the statement of centrifugal force, we know that any

$\frac{G M m}{r^{2}}=m \omega^{2} r$

The orbit’s period is given by,

$T=\sqrt{\frac{2 \pi}{\omega r^{2}}}=\sqrt{\frac{r^{3}}{G M}}$

Where,

$T_{e}$ = Earth’s period

$T_{p}$ = planet’s period

$M_{s}$ = sun’s mass

$r_{e}$ = earth’s radius

Now,

$T_{e}=\sqrt{\frac{r_{e}^{3}}{G M_{s}}}$

As, planet mass is equal to 0.7 times the sun mass, so

$T_{p}=\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}$

Taking the ratios of both equation, we get,

$\frac{T_{e}}{T_{p}}=\frac{\sqrt{\frac{r_{e}^{3}}{G M_{s}}}}{\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}}$

$\frac{T_{e}}{T_{p}}=\sqrt{\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}}$

$\left(\frac{T_{e}}{T_{p}}\right)^{2}=\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}$

$\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}=\frac{r_{e}^{3}}{r_{p}^{3}}$

$\frac{r_{e}}{r_{p}}=\left(\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}$

Given $T_{p}=9.5 \text { days }$ and $T_{e}=365 \text { days }$

$\frac{r_{e}}{r_{p}}=\left(\left(\frac{365}{9.5}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=\left(\frac{133225}{90.25} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=(2108.82)^{\frac{1}{3}}$

$r_{p}=\left(\frac{1}{(2108.82)^{\frac{1}{3}}}\right) r_{e}=\left(\frac{1}{12.82}\right) r_{e}=0.078 r_{e}$

7 0

3 years ago

Coal as a fuel source led to the invention of

Ludmilka [50]

Answer:

coal as a fuel source led to the invention of the printing press i think

8 0

4 years ago

A body of mass 400 kg is suspended at a lower end of a light vertical chain and is being pulled up vertically. Initially the bod

yKpoI14uk [10]

Answer:31.62 m/s

Explanation:

Given

mass of body $m=400 kg$

Pull on chain is $F_1=6000g N=60 kN$

Pull get smaller at the rate of $F_2=360g N/m$

Net Upward Force $F=6000 g-360 g\times 10=24 kN$

net acceleration $a=\frac{F}{m}$

$a=\frac{24\times 1000}{m}$

$a=\frac{24000}{400}$

$a=60 m/s^2$

but g is acting downward

$a_{net}=a-g=60-10=50 m/s^2$

using $v^2-u^2=2 as$

here initial velocity is zero

$v^2=2\times 50\times 10$

$v=31.62 m/s$

7 0

4 years ago

The entropy of an isolated system must be conserved, so it never changes.a. Trueb. Fasle

Snowcat [4.5K]

Answer:

B: False

Explanation:

The second law of thermodynamics states that: the entropy of an isolated system will never decrease because isolated systems always tend to evolve towards thermodynamic equilibrium which is a state with maximum entropy.

Thus, it means that the entropy change will always be positive.

Therefore, the given statement in the question is false.

6 0

3 years ago