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2 years ago

How would you solve for x I cant remember right now 4x+6x=9x-10

Physics

2 answers:

-Dominant- [34]2 years ago

8 0

Combine all of the x's on one side of the equation and then finish the problem!

stepan [7]2 years ago

4 0

So you are first going to want to combine the like terms (in this case, 4x + 6x = 10x) so that the equation is 10x = 9x-10. Next, subtract 9x from both sides.
10x = 9x - 10
-9x -9x
-------------------
x = -10

Sometimes there are more steps, but in general, as long as you do the addition and subtraction before any multiplication, division, or exponential work, you will not have many problems.

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3 years ago

A revolutionary war cannon, with a mass of 2260 kg, fires a 15.5 kg ball horizontally. The cannonball has a speed of 109 m/s aft

Anton [14]

Answer:

The gain in velocity is 0.37m/s

Explanation:

We need solve this problem though the conservation of momentum. That is,

$m_1 v_1 = m_2 v_2$

$m_1=2260Kg\\m_2=15.5Kg\\v_2= 109m/s$

Using the equation to find $v_1$ ,

$v_1=\frac{m_2 v_2}{m_1}\\v_1=\frac{15.5*109}{2260}\\v_1= 0.7475$

Using the conservation of energy equation, we have,

$KE= \frac{1}{2}m*v^2$

$KE_{cball}=\frac{1}{2}(15.5)(109)^2=92077.75J$

$KE_{cannon}=\frac{1}{2}(2260)(0.7475)^2=631.39J$

$Total KE= 92077.75+13425530=92708.9J$

Now this energy over the cannonball

$KE=\frac{1}{2}m*v_2^2$

$92708.9=\frac{1}{2}15.5v_2^2$

$V_2 = 109.37m/s$

The gain in velocity is 0.37m/s

4 0

3 years ago

A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65 m/s in 5 seconds

melisa1 [442]

Answer:

Explanation:

65-35 = 30

30 divided by 5 = 6

The answer will be 6 m/s

6 0

1 year ago

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Ket [755]

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<em>You are correct! **</em>

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3 years ago

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AVprozaik [17]

<h2>Answer:</h2>

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3 years ago