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3 years ago

Are all transmissions fluids interchangeable

Engineering

1 answer:

KiRa [710]3 years ago

6 0

Answer:

<u>No</u>.

Explanation:

They are not all the same. Moreover, using a fluid that is not approved by the vehicle manufacturer will void the transmission warranty.

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A 0.66 ft steel bar undergoes a stretch of 0.75 in in an axial direction. What is the strain? Use three significant figures (fou

Lapatulllka [165]

Answer:

The strain is 0.0947.

Explanation:

Strain is the ration of change in dimension to the original dimension under application of load. Depending upon load, the bar may stretch or compress. So, the strain can be negative in case of compression or positive in case of tension.

Step1

Given:

Original length of the steel bar is 0.66 ft or 7.92 in.

Stretch in the bar is of 0.75 in.

Calculation:

Step2

Strain is calculated as follows:

$e=\frac{\bigtriangleup l}{l_{o}}$

$e=\frac{0.75}{7.92}$

e = 0.0947

Positive sign is for stretching condition of the bar.

Thus, the strain is 0.0947.

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3 years ago

Who is the first presidant of the us?

dexar [7]

Answer:

George Washington was the first president

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3 years ago

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Define schema & Instance...<br><br><br>don't spam..<br>

zubka84 [21]

Answer:

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3 years ago

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for the given sand, the maximum and minimum dry unit weights are 108 lb/ft3 and 92 lb/ft3, respectively. given that Gs=2.65, det

raketka [301]

Answer:

The moist unit weight of compaction = 109.05 lb/ft3

Explanation:

In order to determine the moist unit weight, the dry unit weight has to be evaluated first. If Y is the moist unit weight, then:

Y = Yd (1 + m)

Where:

Yd = dry unit weight

m = moisture content of soil = 8% = 0.08

But the dry unit weight is unknown. In order to calculate the dry unit weight, we will make use of the formula for relative density R;

R = [(Yd — Ydmin) ÷ (Ydmax — Ydmin)] × [Ydmax ÷ Yd]

Where:

R = relative density = 60% = 0.6

Yd = dry unit weight

Ydmin = minimum dry weight = 92 lb/ft3

Ydmax = maximum dry weight = 108 lb/ft3

Therefore R = 0.6 = [(Yd — 92) ÷ (108 — 92)] × [108/Yd]

0.6 = [(Yd — 92)/16] × [108/Yd], or

0.6 = (0.0625Yd — 5.75) × [108/Yd]

0.6Yd = 6.75Yd — 621

6.75Yd — 0.6 Yd = 621

6.15Yd = 621

And Yd = 100.98 lb/ft3 = dry unit weight

But we are asked to find the moist unit weight = Y = Yd (1 + m)

where Yd = dry unit weight and m = moisture content of soil = 8% = 0.08

Therefore, Y = 100.98 (1 + 0.08) = 109.05 lb/ft3.

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3 years ago

A truck with heaped capacity of 10 cy is used to disposed to excavated material at dumpsite of 5 miles from the job site. The av

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Answer:

See the attached diagram containing the detailed solution

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