Answer:
Safety valves are part of the safety features placed in the system to prevent the system from experiencing over pressures
Explanation:
A safety valve is a valve that is actuated automatically when the pressure on the inlet portion rises to a specified value to allow the outflow or discharge of fluid such as liquid, steam or gas out of the system to prevent the system pressure limit from being exceeded. The design of safety valves is such that the valve closes the emergency outlet port again once the system pressure returns to normal.
Airtight plugs are installed in the ends of large sizes of PVC conduit before bending to A. prevent the conduit from collapsing when heated.
<h3>What is
Airtight plugs?</h3>
Airtight plugs is necessary in the PVC conduit so as to be able to avoid the collapse of conduit.
In this case, Airtight plugs are installed in the ends of large sizes of PVC conduit before bending to A. prevent the conduit from collapsing when heated.
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Answer:
The surface temperature of the chip 39.99°C
Explanation:
Assumptions
1. Steady state condition.
2. Power dissipated within the chip is lost by convection across upper surface only.
3. Chip surface is isothermal
4. The average heat transfer coefficient for the chip surface is equivalent to the local value x - L
Properties: from table. See attachment (4)
See attachment for complete solution to the problem
i had problem submitting the answer in the answer box
Answer:
Check the attached images below.
Explanation:
It Is required to develop an approximate relation between . Reynolds and Grashor numbers such that the heat-transfer coefficients for pure forced convection and pure .e convection are equal, assuming laminar flow, by comparing the heat-transfer coefficients for forced or free convection over vertical hat plates.
write the equation or heat transfer coefficient Mr (arced comedian.
Kindly check the attached images below.
Answer:
heat transfer rate is -15.71 kW
Explanation:
given data
Initial pressure = 4 bar
Final pressure = 12 bar
volumetric flow rate = 4 m³ / min
work input to the compressor = 60 kJ per kg
solution
we use here super hated table for 4 bar and 20 degree temperature and 12 bar and 80 degree is
h1 = 262.96 kJ/kg
v1 = 0.05397 m³/kg
h2 = 310.24 kJ/kg
and here mass balance equation will be
m1 = m2
and mass flow equation is express as
m1 =
.......................1
m1 =
m1 = 1.2353 kg/s
and here energy balance equation is express as
0 = Qcv - Wcv + m × [ ( h1-h2) +
+ g (z1-z2) ] ....................2
so here Qcv will be
Qcv = m × [
] ......................3
put here value and we get
Qcv = 1.2353 × [ {-60}+ (310.24-262.96) ]
Qcv = -15.7130 kW
so here heat transfer rate is -15.71 kW