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Mrac [35]
3 years ago
15

In a chemical reaction you collect 1000 mL of hydrogen gas at STP how many moles of hydrogen gas did you collect

Chemistry
2 answers:
Katyanochek1 [597]3 years ago
8 0
Since there are 22.4 L/mol at STP, you would convert 1000mL to 1 L then divide that by 22.4, meaning your answer would be 0.0446 rounded to 0.04
mylen [45]3 years ago
4 0

Answer:

Option B = 0.04 mol

Explanation:

We were given the following:

Pressure = 1 atm (We know this because it was stated that the gas is at STP).

Volume = 1000ml = 1L (Converting to L by diving by 1000)

Temperature = 273.15k (We know this because it was stated that the gas is at STP).

We are to calculate the number of moles, n collected.

The Ideal Gas Equation relates all of these variables;

pV=nRT

where R = gas constant = 0.08206 L atm / K mol

making n subject of interest, we have;

n=pV / RT

Substituting the values of the variables and solving for n;

n = (1 * 1 ) / (0.08206 * 273.15)

n = 0.0446 mol

Approximately, n = 0.04 mol

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How many milliliters of 0.150 M NaOH are required to neutralize 85.0 mL of 0.300 M H2SO4 ? The balanced neutralization reaction
nekit [7.7K]

Answer : The volume of NaOH required to neutralize is, 340 mL

Explanation :

To calculate the volume of base (NaOH), we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.300M\\V_1=85.0mL\\n_2=1\\M_2=0.150M\\V_2=?

Putting values in above equation, we get:

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3 years ago
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