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3 years ago

Describe where each subatomic particle is found in an atom.

Physics

2 answers:

Artemon [7]3 years ago

4 0

Answer:

Protons and neutrons are found in the nucleus, and electrons are found in the circles, or orbits, around the nucleus.

Explanation:

Anestetic [448]3 years ago

3 0

Answer:

In the nucleus

Explanation:

You find it in the nucleus. This is where protons and neutrons are. Don't forget the quarks as well ;)

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Object A is negatively Charged. object A and Object B attract. Object B and Object C repel. Object C and Object D attract. What

3241004551 [841]

Remember opposites attract and same charges repel each other.

Object A= negatively charged.

Object A and B attract so B must be positively charged.

Object B and C repel so because B is positively charged C must also be positively charged.

Object C and D attract and because C is positively charged, D must be negatively charged.

5 0

4 years ago

An object with a mass of 2.00 kg is placed at the end of a spring, having a spring constant of 180.0 N/m. The spring is then com

s2008m [1.1K]

Answer:

the velocity of the mass is 8.44 m/s

Explanation:

Given;

mass of the object, m = 2 kg

spring constant, k = 180 N/m

extension of the spring, x = 0.89 m

The maximum velocity of the mass is calculated as follows;

By the principle of conservation of energy;

Elastic potential energy = kinetic potential energy

¹/₂kx² = ¹/₂mv²

kx² = mv²

$v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{180 \times 0.89^2}{2} }\\\\v = 8.44 \ m/s$

Therefore, the velocity of the mass is 8.44 m/s

8 0

3 years ago

If an automobile's velocity changes from 25 m/s to 15m/s in 2s, then what is its acceleration?

tekilochka [14]

Hey!

u=25m/s
v=15m/s
t=2s
a=?

v-u=at
15-25=a×2
-10=2a
-10/2=a
a=-5m/s^2

Hope it helps...!!!

8 0

4 years ago

A truck, initially at rest, rolls down a frictionless hill and attains a speed of 20 m/s at the bottom. To achieve a speed of 40

Crank

Answer:

To achieve the velocity of 40 m/sec height will become 4 times

Explanation:

We have given initially truck is at rest and attains a speed of 20 m/sec

Let the mass of the truck is m

At the top of the hill potential energy is mgh and kinetic energy is $\frac{1}{2}mv^2$

So total energy at the top of the hill $=mgh+0=mgh$

At the bottom of the hill kinetic energy is equal to $\frac{1}{2}mv^2$ and potential energy will be 0

So total energy at the bottom of the hill is equal to $0+\frac{1}{2}mv^2$

Form energy conservation $mgh=\frac{1}{2}mv^2$

$v=\sqrt{2gh}$ , for v = 20 m/sec

$20=\sqrt{2\times 9.8\times h}$

Squaring both side

$19.6h=400$

h = 20.408 m

Now if velocity is 0 m/sec

$40=\sqrt{2gh}$

$19.6h=1600$

h = 81.63 m

So we can see that to achieve the velocity of 40 m/sec height will become 4 times

5 0

3 years ago

A local FM radio station broadcasts at a frequency of 97.3 MHz. Calculate the energy of the frequency at which they are broadcas

levacccp [35]

Answer:

6.45×10¯²⁶ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 97.3 MHz

Energy (E) =?

Next, we shall convert 97.3 MHz to Hz. This can be obtained as follow:

1 MHz = 1×10⁶ Hz

Therefore,

97.3 MHz = 97.3 MHz × 1×10⁶ Hz / 1 MHz

97.3 MHz = 9.73×10⁷ Hz

Thus, 97.3 MHz is equivalent to 9.73×10⁷ Hz.

Finally, we shall determine the energy at which the frequency is broadcasting. This can be obtained as follow:

Frequency (f) = 9.73×10⁷ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 9.73×10⁷

E = 6.45×10¯²⁶ J

Therefore, the energy at which the frequency is broadcasting is 6.45×10¯²⁶ J

5 0

3 years ago