Answer:
1.The force required to stop the shopping cart is, F = 12.25 N
Explanation:
Given data,
The mass of the shopping cart, m = 7 kg
The initial velocity of the shopping cart, u = 3.5 m/s
The final velocity of the shopping cart, v = 0 m/s
The time period of acceleration, t = 2 s
The change in momentum of the cart,
p = m(u - v)
= 7 (3.5 - 0)
= 24.5 kg m/s
The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula
F = p / t
= 24.5 / 2
= 12.25 N
Hence, the force required to stop the shopping cart is, F = 12.25 N
2.
We have: F = m × v/t
Here, m = 8500 Kg
v = 20 m/s
t = 10 s
Substitute their values into the expression,
F = 8500 × 20/10
F = 8500 × 2
F = 17000 N
In short, final answer would be 17000 N
Hope this helps!!
A) We balance the masses: 4(1.00728) vs 4.0015 + 2(0.00055)4.02912 vs. 4.0026This shows a "reduced mass" of 4.02912 - 4.0026 = 0.02652 amu. This is also equivalent to 0.02652/6.02E23 = 4.41E-26 g = 4.41E-29 kg.
b) Using E = mc^2, where c is the speed of light, multiplying 4.41E-29 kg by (3E8 m/s)^2 gives 3.96E-12 J of energy.
c) Since in the original equation, there is only 1 helium atom, we multiply the energy result in b) by 9.21E19 to get 3.65E8 J of energy, or 365 MJ of energy.
Explanation:
The x component of the resultant force is the sum of the x components of the individual forces.
Fₓ = 65.0 cos 30° − 20.0 sin 20° − 30.0
Fₓ = 19.5
The y component of the resultant force is the sum of the y components of the individual forces.
Fᵧ = 65.0 sin 30° − 20.0 cos 20°
Fᵧ = 13.7
The magnitude is found with Pythagorean theorem:
F² = Fₓ² + Fᵧ²
F² = (19.5)² + (13.7)²
F = 23.8
Answer:
1. 18.5m/s
2. 17.5 m
3. 0 at its highest point
4. Direction is downwards
Explanation:
1. This egg is thrown vertically from a height
Yo = 0. This egg then falls to the point y = -30.0 at t = 5seconds
Y-Yo = V0t - 1/2gt²
-30-0 = V0(5)-1/2(9.8)(5²)
-30 = 5v0 - 4.9x25
-30 = 5V0 - 122.5
-30+122.4 = 5v0
V0 = 92.5/5
= 18.5m/s
<em><u>this </u></em><em><u>is </u></em><em><u>the </u></em><em><u>initial</u></em><em><u> </u></em><em><u>speed</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>egg</u></em>
2. When the egg is at a maximum height it would have a velocity equal to 0
V² = V0² - 2*g*y
V = 0, V0 = 18.5, g = 9.8
0 = 18.5²-2x9.8*y
342.25-19.6y = 0
342.25 = 19.6y
Divide through by 19.6
Y = 342.25/19.6
Y = 17.5m
<em><u>this value is how high it rises above starting point</u></em>
3.
The magnitude of velocity is = 0 at its highest point
4.
This egg falls under gravity. Therefore the acceleration due to gravity has a constant magnitude and direction. Magnitude = 9.8m/s and it's direction is downwards.
5. Please check attachment for graph
Heaver objects because they have greater mass
