What is the probability that no 1s will be in the output for an input sequence of 10 digits??
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The polynomial P(x) expressed in the form P(x) = d(x).Q(x) + R(x) is x³ + 8 = (x+2)(x² -2x + 4) + 0
<h3>Dividing polynomials</h3>From the question, we are to divide the given polynomial P(x) by the divisor d(x)
From the given information,
P(x) = x³ + 8
d(x) = x + 2
The division operation is shown in the attachment below.
The quotient, Q(x) = x² -2x + 4
and the remainder, R(x) = 0
We area to express P(x) in the form
P(x) = d(x).Q(x) + R(x)
Thus, we get
x³ + 8 = (x+2)(x² -2x + 4) + 0
Hence, the polynomial P(x) expressed in the form P(x) = d(x).Q(x) + R(x) is x³ + 8 = (x+2)(x² -2x + 4) + 0
Learn more on Dividing polynomials here: brainly.com/question/27601809
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