What is the probability that no 1s will be in the output for an input sequence of 10 digits??
1 answer:
The total numbers with 10 digits are 9*10*10*10*10*10*10*10*10*10 = 9*(10^9)
If you are restricted to use no 1s, the numbers are 8*(9^9)
Then, the probability is : numbers with no 1s / total numbers
= 8*(9^9) / [9*(10^9)]= 0.344
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