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katrin [286]
4 years ago
12

What is the probability that no 1s will be in the output for an input sequence of 10 digits??

Mathematics
1 answer:
emmasim [6.3K]4 years ago
5 0
The total numbers with 10 digits are 9*10*10*10*10*10*10*10*10*10 = 9*(10^9)

If you are restricted to use no 1s, the numbers are 8*(9^9)

Then, the probability is : numbers with no 1s /  total numbers

 = 8*(9^9) / [9*(10^9)]= 0.344
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There are 2 tangent lines that pass through the point

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Explanation:

Given:

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For the lines to be tangent to the curve, we must substitute the first derivative of the curve for m:

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Because the line must touch the curve, we may substitute y=\frac{x}{x+1}:

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x\frac{-4±\sqrt{4^2-4(1)(1)} }{2(1)}

x=-2 ± \sqrt{3}

x=-2 ± \sqrt{3}<em> </em>and x=-2-\sqrt{3}

There are 2 tangent lines.

y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2

and

y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2

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