What is the probability that no 1s will be in the output for an input sequence of 10 digits??

1 answer:

5 0

The total numbers with 10 digits are 9*10*10*10*10*10*10*10*10*10 = 9*(10^9)

If you are restricted to use no 1s, the numbers are 8*(9^9)

Then, the probability is : numbers with no 1s / total numbers

= 8*(9^9) / [9*(10^9)]= 0.344

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