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Alex73 [517]
3 years ago
8

Nuclear power plants produce energy using fission. One common fuel, uranium-235, produces energy through the fission reaction 23

5 92U+10n→fission fragments+neutrons+3.20×10−11 J/atom 92235U+01n→fission fragments+neutrons+3.20×10−11 J/atom What mass of uranium-235 is needed to produce the same amount of energy as the fusion reaction in Part A? Express your answer to three significant figures and include the appropriate units.
Chemistry
1 answer:
Vikentia [17]3 years ago
7 0

Answer:

mass of U-235  = 15.9 g (3 sig. figures)

Explanation:

1 atom can produce -------------------------> 3.20 x 10^-11 J energy

x atoms can produce ----------------------> 1.30 x 10^12 J energy

x = 1.30 x 10^12 / 3.20 x 10^-11

x = 4.06 x 10^22 atoms

1 mol ----------------------> 6.023 x 10^23 atoms

y mol ----------------------> 4.06 x 10^22 atoms

y = 0.0675 moles

mass of U-235 = 0.0675 x 235 = 15.8625

mass of U-235  = 15.9 g (3 sig. figures)

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How many water molecules are produced when 5.2g O2 are reacted
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Answer:

Total number of water molecules produced after the reaction is 1.956×10^22 molecules of water.

Explanation:

By the reaction

H2+ 1/2 O2 → H2O

Moles of O2 = 5.2\32

⇒1 mole of O2 produce 1  mole of H2O

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Therefore, 5.2\32 mole will produce {2}\times{\frac{5.2}\times{32}}

⇒ Molecules of H2O  will be

         {2}\times{\frac{5.2}{32}} = \frac{x}{{6.02}\times{10^23}}

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Calcular la fraccion molar de NaClO en una solucion blanqueadora comercial que comtiene 3,62% en masa de NaClO en agua
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<em>Calculate the molar fraction of NaClO in a commercial bleach solution that contains 3.62% by mass of NaClO in water</em>

<em />

<h3>Further explanation</h3>

convert mass to mol

mol NaClO (MW=74.5 g/mol) :

\tt \dfrac{3.62}{74.5}=0.0486

mol H₂O (MW= 18 g/mol) :

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