How many moles are in 30g of C12H22O11?
2 answers:
You first want to set up an equation like the one I did then you break down
C12H22O11 and find their molar masses C= (how ever many you have which is 12) x molar mass 12.011= 144.132
H = 22 x 1.008 = 22.176
O= 11 x 15.999 =175.989
And then you add 144.132 + 22.176 + 175.989= 342.297g (that’s your molar mass for C12H22O11 ) and then you want to divide it by the 30g you already have because you want to cancel out grams and get moles.
C12H22O11 and find their molar masses C= (how ever many you have which is 12) x molar mass 12.011= 144.132
H = 22 x 1.008 = 22.176
O= 11 x 15.999 =175.989
And then you add 144.132 + 22.176 + 175.989= 342.297g (that’s your molar mass for C12H22O11 ) and then you want to divide it by the 30g you already have because you want to cancel out grams and get moles.
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Answer:
a) 72 °F= 22.22 °C
b) 213.8 °C= 416.84°F
c) 180 °C= 453.15 °K
d) 315 °K= 107.33 °F
e) 1750 °F= 1227.594 °K
f) 0 °K= -459.67 °F
Explanation:
Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:
- Fahrenheit a Celsius:
- Celsius a Fahrenheit: °F= °C*1.8 + 32
- Celsius a Kelvin: °K= °C + 273.15
- Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32
- Fahrenheit a Kelvin:
Entonces se obtiene:
a) 72 °F= =22.22 °C
b) 213.8 °C= 213.8*1.8 + 32= 416.84°F
c) 180 °C= 180°C + 273.15= 453.15 °K
d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F
e) 1750 °F= = 1227.594 °K
f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F