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nexus9112 [7]
3 years ago
9

A can of soda is 335ml what is 2 cans of soda in ml

Chemistry
1 answer:
Snezhnost [94]3 years ago
5 0
I can =335ml
2cans=?

2cans×335ml÷1
= 670ml
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Please help with this, i don't really get how to do this
LuckyWell [14K]
#4 and #5:
To find pH given concentration of H+ or H30+
pH = - log (H+ or H30+ M)

To find pH given concentration of OH-
Since you already found the pH for this (in #4), you subtract #4's answer from 14.
14 - (pH) = pOH
8 0
3 years ago
The bonds of the product store 27 KJ more energy than the bonds of the reactants how is energy conserved during this reaction
Blababa [14]

If the bonds of the product store 27 KJ more energy than the bonds of the reactants, It means the surroundings absorb 27 kj of energy from the reaction system Hence, Option (D) is the correct answer

<h3>What is the Exothermic reaction ?</h3>

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise.

The bonds of the product store 27 KJ more energy than the bonds of the reactants, It means that energy has been absorbed by the surrounding as the product formed is more stable due to more stronger bond

This can be inferred from more stored energy with in the bonds and Thus, It is a exothermic reaction.Hence, Option (D) is the correct answer

Learn more about exothermic reaction here ;

brainly.com/question/9799465

#SPJ1

6 0
2 years ago
Will marks brainly if it isn’t a copied answer!!!
Neporo4naja [7]

What kind of control like scientific?

5 0
2 years ago
Read 2 more answers
How many grams of diphosphorus pentoxide result if 100.0 g of phosphorus are combined with sufficient oxygen?
gregori [183]
Answer is: 230 g.
Chemical reaction: P₄ + 5O₂ → 2P₂O₅.
m(P₄) = 100 g.
M(P₄) = 4 · 31 g/mol = 124 g/mol.
n(P₄) = m(P₄) ÷ M(P₄) = 100g ÷ 124g/mol = 0,806 mol.
From reaction: n(P₄) : n(P₂O5) = 1 : 2.
n(P₂O₅) = 1,612 mol.
m(P₂O₅) = 1,612 mol · 142g/mol = 230g.
M - molar mass.
n - amount of substance.
3 0
3 years ago
An endergonic reaction with a Δh and Δs can be changed into an exergonic reaction.
zheka24 [161]

Full question:

This question is incomplete, here it is completed:

An endergonic reaction with a ______ ∆H and a ______ ∆S can be changed into an exergonic reaction by decreasing the temperature.

Option A: negative, positive

Option B: negative, negative

Option C: positive, positive

Option D: positive, negative

Answer:

Option B: negative, negative

Explanation:

The change in free energy (ΔG) of a system for a constant-temperature process is

ΔG = ΔH - TΔS

free energy is the energy available to do work. Thus, if a particular reaction is accompanied by a release of usable energy (that is, <u>ΔG is negative</u><u>), it is said to be</u><u> exergonic</u>. On the other hand, if a reaction consumes energy (that is, <u>ΔG is positive</u><u>), it is said to be </u><u>endergonic</u>.

Looking at the equation, we can see that if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS  is smaller in magnitude than ΔH. This condition is met when T is small.

ΔG = ΔH - TΔS

           -        -

This means that the reaction proceeds spontaneously at low temperatures. At high temperatures, the reverse reaction becomes spontaneous. An example of that would be the following reaction:

NH₃(g) + HCl(g) → NH₄Cl(s)

4 0
3 years ago
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