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antiseptic1488 [7]
4 years ago
15

PLEASE HELP ME ASAP ILL MARK U AS BRILLIANT

Chemistry
1 answer:
faust18 [17]4 years ago
6 0

Answer:

19 D

20 C

21 B

22 A

23 A

24 A

Explanation:

See the periodic table

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Which characteristic is true of sexual reproduction but not of asexual reproduction?
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Answer:

Sexual Reproduction involves two different parties

Explanation:

Asexual is the opposite, so it uses no one else to reproduce

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Increasing the temperature of a particular liquid from 298 K to 318 K causes its vapor pressure to double. What is the enthalpy
Delvig [45]

Answer:

27.3 kJ/mol

Explanation:

Step 1: Given data

  • Temperature 1 (T₁): 298 K
  • Vapor pressure 1 (P₁): P₁
  • Temperature 2 (T₂): 318 K
  • Vapor pressure 2 (P₂): 2 P₁

Step 2: Calculate the enthalpy of vaporization of this liquid

We will use the Clausius–Clapeyron equation.

ln (P₂/P₁) = -ΔHvap/R × (1/T₂ - 1/T₁)

ln 2 = -ΔHvap/(8.314 J/K.mol) × (1/318 K - 1/298 K)

ΔHvap = 2.73 × 10⁴ J/mol = 27.3 kJ/mol

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3 years ago
Explain in your own words what empirical evidence is.
zhuklara [117]
Empirical evidence is information acquired by observation or experimentation
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What is a harmful role of bacteria?
zzz [600]

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sickness.

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some bacterium cause sickness, kike a stomach bug.

6 0
4 years ago
I know that the answer is C. 8, but can you explain step by step how to get that answer?
Leya [2.2K]

Answer:

8

Explanation:

Oxidation:

Fe^{2+} -->Fe^{3+}+e^{-}

Reduction:

Cr_{2}O_{7}^{2-}+6e^{-} -->2Cr^{3+}

We have to equalise the number  of moles of electrons gained and lost in a redox reaction in order to get a balanced reaction.

Hence we have to multiply the oxidation reaction throughout by 6.

and adding the two half-reactions we obtain:

6Fe^{2+}+Cr_{2}O_{7}^{2-} -->6Fe^{3+}+2Cr^{3+}

Still the total charge and number of oxygen is not balanced.

Since the reaction takes place in acidic conditions, we will add required number of H+ to the appropriate side to balance the charge and add half the amount of H2O to balance the hydrogen atoms.

We add 14 H+ on LHS and 7H2O on RHS to obtain:

6Fe^{2+}+Cr_{2}O_{7}^{2-}+14H^{+} -->6Fe^{3+}+2Cr^{3+}+7H_{2}O

Sum of coefficients of product cations = 6+2 = 8

4 0
3 years ago
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