Answer:
(a) 43.2 kC
(b) 0.012V kWh
(c) 0.108V cents
Explanation:
<u>Given:</u>
- i = current flow = 3 A
- t = time interval for which the current flow =
- V = terminal voltage of the battery
- R = rate of energy = 9 cents/kWh
<u>Assume:</u>
- Q = charge transported as a result of charging
- E = energy expended
- C = cost of charging
Part (a):
We know that the charge flow rate is the electric current flow through a wire.
Hence, 43.2 kC of charge is transported as a result of charging.
Part (b):
We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:
Hence, 0.012V kWh is expended in charging the battery.
Part (c):
We know that the energy cost is equal to the product of energy expended and the rate of energy.
Hence, 0.108V cents is the charging cost of the battery.
Answer:
a.work done=force *displacement
=500N*46m
=23000 Joule
b.power=work done/time taken
=23000/25
=920 watt
c.GPE=m*g*h(m=mass,g=gravity due to acceleration,h=height)
=60kg*9.8m/s*14m
=8232 joule
Explanation:
The right answer for the question that is being asked and shown above is that: "C. <span>. The properties change going across each row. " the </span>statement that applies to the horizontal rows or periods in the periodic table is that t<span>he properties change going across each row. </span>
Given data in the problem :-
- Acceleration (a) = 4.0 m/s^2
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 34 m/s
- Distance travelled by aircraft (S) = ?
From Newton's Laws of Motion we know that ,
v = u + at [t = Time taken by aircraft to cover the distance]
⇒ 34 = 0 + 4t
⇒ t = 34/4 s
∴ t = 8.5 s
From Newton's Laws of Motion we also know that ,
S = u.t + 1/2a.t^2
⇒ S = 0×8.5 + 1/2 × 4 × (8.5)^2 m
∴ S = 144.50 m
Thus the distance travelled by the aircraft while accelerating is 144.50 meter .
Given:
u = 10⁵ m/s, the entrance velocity
v = 2.5 x 10⁶ m/s, the exit velocity
s = 1.6 cm = 0.016 m, distance traveled
Let a = the acceleration.
Then
u² + 2as = v²
(10⁵ m/s)² + 2*(a m/s²)*(0.016 m) = (2.5 x 10⁶ m/s)²
0.032a = 6.25 x 10¹² - 10¹⁰ = 6.24 x 10¹²
a = 1.95 x 10¹⁴ m/s²
Answer: 1.95 x 10¹⁴ m/s²
