Answer:


Explanation:
<u>Given:</u>
Mass = m = 200,000 kg
Vertical Distance = h = 120 m
Speed = v = 14 m/s
Acceleration due to gravity = g = 10 m/s²
<u>Required:</u>
1) Gravitational Potential Energy = P.E = ?
2) Kinetic Energy = K.E. = ?
<u>Formula:</u>
1) P.E. = mgh
2) K.E. = 
<u>Solution:</u>
1) P.E. = (200,000)(10)(120)
P.E. = 240,000,000 Joules
P.E. = 240 Mega Joules
P.E. = 240 MJ
2) K.E. = 1/2 (200000)(14)^2
K.E. = (100000)(196)
K.E. = 19,600,000 Joules
K.E. = 19.6 MJ
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
As per kinematics equation we know that
final speed of the car = 0 m/s
initial speed is given as 30 m/s
distance moved = 100 m
now we have



now braking force is given as

now for mass we know that the weight of car is

so mass of car is

now we have

Part b)
Again we have
final speed of the car = 0 m/s
initial speed is given as 30 m/s
distance moved = 10 m
now we have



now braking force is given as

mass of car is

now we have

Answer:
if the mass of both objects is doubled, then the force of gravity between them is quadrupled and so on
Answer:
D
Explanation:
I am assuming that you got to go up to Zak as his editor and tell him in his face if he is doing the work correctly. Dont trust me though, cause C also looks plausible