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BabaBlast [244]
3 years ago
7

Why energy must be added to a solid to cause it to melt.

Physics
1 answer:
Art [367]3 years ago
7 0
Heat is a form of energy, and heat melts objects
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The loudness of sound is determined by what?
baherus [9]
The amplitude of a sound<span> wave </span>determines<span> its </span>loudness<span> or volume. A larger amplitude means a louder </span>sound<span>, and a smaller amplitude means a softer </span><span>sound</span>
5 0
3 years ago
Read 2 more answers
How much heat is needed to raise the temperature of 5g of water by 20oC?
Ratling [72]
Required Heat = Q

Q = Mass * specific heat of water * change in temp.

Q = 5g * 1g/cal*degC * 20degC

Q = 100 cal of heat is required

To convert calories to Joules,
1 cal = 4.184 Joules

100cal = 418.4 J of heat is needed
5 0
3 years ago
If the worlds human population stay away from all the fast foods that they purchase and consume their overall physical and menta
Nadusha1986 [10]

Hi ChloeRenee12345,

Your Question:

If the worlds human population stay away from all the fast foods that they purchase and consume their overall physical and mental state would be greatly affected

Answer:

Well absolutely not! Everyone will not be affected by not purchasing fast food, It will actually be better for the society. Fast food has bad properties that makes people get fat.

5 0
3 years ago
The longer the wavelength, the lower the frequency, and the lower the energy. Lesson 4.07 True False​
jenyasd209 [6]
It’s true. longer wavelength means a lower frequency, and a shorter wavelength means a higher frequency!
3 0
3 years ago
Consider your favorite radio station. AM radio has a frequency between 535 kilohertz and 1605 kilohertz, and FM radio has a freq
zzz [600]

Answer

The wavelength for 550 kHz signal is

             \lambda = \dfrac{3.00 \times 10^8}{550\times 10^3}

                         λ = 545.45 m

The wavelength for 1600 kHz signal is

              \lambda = \dfrac{3.00 \times 10^8}{1600\times 10^3}

                         λ = 187.5 m                        

The wavelength for 88 MHz signal is

              \lambda = \dfrac{3.00 \times 10^8}{88\times 10^6}

                         λ = 3.41 m

The wavelength for 108 MHz signal is

             \lambda = \dfrac{3.00 \times 10^8}{108\times 10^6}

                         λ = 2.78 m

7 0
3 years ago
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