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Gala2k [10]
3 years ago
9

Many protists are single-celled organisms. Which of the following characteristics is also common to organisms in Kingdom Protist

a?
A.
thrive in environments without oxygen

B.
thrive in environments with little sunlight

C.
thrive in wet environments

D.
thrive in environments without water
Chemistry
2 answers:
Alenkinab [10]3 years ago
8 0

THE ANSWER IS C I JUST TOOK THE TEST. THE ANSWER IS ::::

thrive in wet environments

HACTEHA [7]3 years ago
6 0

Protists belong to the group eukaryotes (having their DNA enclosed inside the nucleus). They are not plants, nimals or fungi but they act like one. They can be in general subgroups such as unicellular algae, protozoa and molds. They thrive in environments with little sunlight. The answer is letter B.

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What do scientist do to easily share measurement data they can understand
Jobisdone [24]
1. They use the same measuring system (metric)

2. Clearly and properly collect and record data, recording the procedure and results

3. Releasing the data into the public, letting everyone have access to it

maybe, I don't know what answer your teacher wants
3 0
3 years ago
What is the mass in grams of 9.45*10^24 molecules of methanol (CH3OH)?
Angelina_Jolie [31]
Number of moles:

1 mole ---------- 6.02x10²³ molecules
? moles --------- 9.45x10²⁴ molecules

1 x ( 9.45x10²⁴) / 6.02x10²³ =

9.45x10²⁴ / 6.02x10²³ => 15.69 moles of CH3OH

Therefore:

Molar mass CH3OH = 32.04 g/mol

1 mole ------------ 32.04 g
15.69 moles -----  mass methanol

Mass methanol  = 15.69 x 32.04 / 1 => 502.7076 g


6 0
3 years ago
What is the solubility of argon (in units of grams per liter) in water at 25 °C, when the Ar gas over the solution has a partial
beks73 [17]

Answer:

0.02405 g/L is the solubility of argon  in water at 25 °C.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{Ar}=K_H\times p_{gas}

where,

K_H = Henry's constant = 1.40\times 10^{-3}mol/L.atm

p_{Ar} = partial pressure of carbonated drink = 0.51atm

Putting values in above equation, we get:

C_{Ar}=1.40\times 10^{-3}mol/L.atm\times 0.430 atm\\\\C_{Ar}=6.02\times 10^{-4}mol/L

Molar mass of argon = 39.95 g/mol

Solubility of the argon gas :

6.02\times 10^{-4}mol/L\times 39.95 g/mol=0.02405 g/L

0.02405 g/L is the solubility of argon  in water at 25 °C.

5 0
4 years ago
Instant cold packs, often used to ice athletic injuries on the field, contain ammonium nitrate and water separated by a thin pla
RSB [31]

<u>Answer:</u> The enthalpy change of the reaction is -27. kJ/mol

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 25.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{25.0mL}\\\\\text{Mass of water}=(1g/mL\times 25.0mL)=25g

To calculate the heat released by the reaction, we use the equation:

q=mc\Delta T

where,

q = heat released

m = Total mass = [1.25 + 25] = 26.25 g

c = heat capacity of water = 4.18 J/g°C

\Delta T = change in temperature = T_2-T_1=(21.9-25.8)^oC=-3.9^oC

Putting values in above equation, we get:

q=26.25g\tiimes 4.18J/g^oC\times (-3.9^oC)=-427.9J=-0.428kJ

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of ammonium nitrate = 1.25 g

Molar mass of ammonium nitrate = 80 g/mol

Putting values in above equation, we get:

\text{Moles of ammonium nitrate}=\frac{1.25g}{80g/mol}=0.0156mol

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = -0.428 kJ

n = number of moles = 0.0156 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{-0.428kJ}{0.0156mol}=-27.44kJ/mol

Hence, the enthalpy change of the reaction is -27. kJ/mol

4 0
3 years ago
Can someone please help me please
GaryK [48]

Liquids have more kinetic energy in their particles compared to solids. this allows the particles to move more freely, hence why they are fluids


Liquids diffuse from a region of high concentration to a region of low concentration, until equilibrium is reached


When heat is applied the particles gain more kinetic energy so they now have enough energy to overcome the bonds holding them in the liquid. this means they can evaporate off

8 0
3 years ago
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