Which of the following is NOT true regarding the far side of the moon:

What is the acceleration of a ball traveling horizontally with an initial velocity of 20 meters/second and, 2.0 seconds later, a

Nutka1998 [239]

The acceleration of the ball is 5 m/s^2. This can be calculated using a formula that relates the change in velocity, acceleration, and time. This formula is:

Vf = Vi + at

where:
Vf = final velocity
Vi = initial velocity
a = acceleration
t = time

Substituting the values gives:

30 = 20 + a(2)
<span>a = 5 m/s^2 --> Final Answer</span>

6 0

2 years ago

Joe and Max shake hands and say goodbye. Joe walks east 0.50 km to a coffee shop, and Max flags a cab and rides north 3.45 km to

timama [110]

Answer:

3.486 km

Explanation:

Suppose Joe and Max's directions are perfectly perpendicular (east vs north). We can calculate their distance at the destinations using Pythagorean theorem:

$s = \sqrt{J^2 + M^2}$

where J = 0.5 km and M= 3.45 km are the distances between Joe and Max to their original parting point, respectively. s is the distance between them.

$s = \sqrt{0.5^2 + 3.45^2} = \sqrt{12.1525} = 3.486 km$

8 0

3 years ago

A merry-go-round is rotating at constant angular speed. Two children are riding the merry-go-round: Ana is riding at point A and

marysya [2.9K]

Answer:

bobby has a greater magnitude of velocity because because when angular speed is constant linear velocity is proportional to radius of the circular path

B. They both have same magnitude of angular velocity since the angular speed of the merrygoround is constant

C. Also they both have the same tangential acceleration because the angular speed is constant and tangential is zero for both of them

D. Centripetal acceleration of Bobby is greater

E.they both have the same angular acceleration because angular Speed I constant so angular acceleration is zero for both

3 0

2 years ago

An object is dropped from rest from a height of 4.1 107 m above the surface of the Earth. If there is no air resistance, what is

Valentin [98]

Answer:

2.83 x 10^4m/s

Explanation:

First, let us calculate the time taken by the object to hit the surface of the earth.

H = 4.1 x 10^7m

g = 9.8m/s2

t = √(2H/g)

t = √((2x 4.1 x 10^7) /9.8)

t = 2892.64secs

Now, we can find the velocity with which the object strikes the earth as follows:

V = gt

V = 9.8 x 2892.64

V = 2.83 x 10^4m/s

3 0

2 years ago

You have arrived at the scene of a two car accident. You know the following pieces of information:

Pani-rosa [81]

The initial velocity of car 1 is 20 m/s to the right

The initial velocity of car 2 is zero

The final velocity of car 2 is 10 m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision.

Therefore, we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$