By applying the wave equation we know that the displacement on the y-axis is 1.999 micrometers.
We need to know about wave equations to solve this problem. The displacement of the wave on the y-axis can be explained by the wave equation
y = A cos (kx - ωt)
where y is y-axis displacement, A is amplitude, k is wave number, x is x-axis displacement, ω is angular speed and t is time.
the wavenumber and angular speed of the wave equation can be determined respectively by
k = 2π / λ
ω = 2πf
where k is the wavenumber, λ is wavelength and f is frequency.
From the question above, we know that:
y = 2.00cos (15.7x - 858t)
(x in meters, t in second, y in micrometers)
x = 0.05 m
t = 3 ms
Convert time to second
t = 3ms = 0.003 s
By applying the wave equation, we get
y = 2.00cos (15.7x - 858t)
y = 2.00cos (15.7(0.05) - 858(0.003))
y = 2 cos(-1.789)
y = 1.999 micrometers
For more on wave equation on: brainly.com/question/25699025
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Answer:
A bear normally has a short, thick neck, a rounded head, a pointed muzzle, short ears, and small eyes. Some species have round faces. Bears have poor eyesight, and most have only fair hearing.
Explanation:
Modern Bears are characterized with large body and stocky legs, a long snout, shaggy hair, plantigrade paws with five non-retractile claws and a short tail.
Grizzly bears (Ursus arctos horribilis) have concave faces, a distinctive hump on their shoulders, and long claws about two to four inches long. Both the hump and the claws are traits associated with a grizzly bear's exceptional digging ability. Grizzlies are often dark brown, but can vary from blonde to nearly black.
The brown bear has a slight hump above its shoulder, round ears, a long snout and big paws with long, curved claws that it uses for digging. Unlike the black bear, it can't climb trees. It can weigh between 350-1,500 pounds. When standing on its hind legs it can be up to 5 feet tall.
Hope this helps :)
(I didn't know which type of bear so i did brown bear and grizzly bear)
Answer:
the answer should be C owo
If swimmers had a choice of the water slides shown in this figure,
they would all go home dry, since there is no figure. I'll have to try to
answer this question based on only the words in the text, augmented
only by my training, education, life experience, and human logic.
-- Both slides are frictionless. So no energy is lost as a swimsuit
scrapes along the track, and the swimmer's kinetic energy at the
bottom is equal to the potential energy he had at the top.
-- Both slides start from the same height. So the same swimmer
has the same potential energy at the top of either one, and therefore
the same kinetic energy at the bottom of either one.
-- So the difference in the speeds of two different swimmers
on the slides depends only on the difference in the swimmers'
mass, and is not influenced by the shape or length of the slides
(as long as the slides remain frictionless).
If both swimmers have the same mass, then v₁ = v₂ .
Before the impact, let the velocity of the baseball was v m/s.
After being hit by the bat its velocity is -2v
So, change in velocity, Deltav=v-(-2v)=3v
Acceleration is defined as the rate of change in velocity, i.e. actual change in velocity divided by the time taken to change it. Time taken to change velocity is the time of actual contact of the bat and ball, i.e. 0.31 s.
a=(Deltav)/(Deltat)
=(3v)/0.37
Therefore, a/v=3/0.31=9.7 s^-1
So, the ratio of acceleration of the baseball to its original velocity is 9.7.
