The elastic potential energy stored in the stretched spring is 1 J.
<h3>What is Hooke's law?</h3>
Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.
Given that;
Force on the spring = 350 Newton
Distance stretched = 7 centimeters or 0.07 m
Hence;
F = ke
k = F/e = 350 Newton/0.07 m = 5000 N/m
Work done in stretching a spring = 1/2ke^2
= 0.5 × 5000 × (2 × 10^-2)^2 =1 J
Learn more about elastic potential energy: brainly.com/question/156316
Answer:
C₁ = 3 pF
C₂ = 6 pF
Explanation:
Let the capacitance be C₁ and C₂.
For parallel combination
C₁ +C₂ = 9
For series combination


C₁ X C₂ = 18
( 9-C₂ )X C₂ = 18
C₂²- 9C₂ +18 = 0
C₂ = 6 or 3.
C₁ = 3 or 6.
C₁ = 3 pF
C₂ = 6 pF
Answer:
Then the rocket will slow down until the end of gas and when all the gases are ended, then it stops at the highest point of space and falls back to earth.
<h2><em><u>NOT</u></em><em><u> </u></em><em><u>COPIED</u></em><em><u> </u></em><em><u>ANSWER</u></em></h2>
Answer: the higher the kinetic energy
Explanation: