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kow [346]
4 years ago
11

A tennis ball is tossed up off a building with a velocity of 22m/s. It takes 6.4s to reach the ground. How high is the building

and what is the maximum height of he tennis ball.
Physics
1 answer:
Amanda [17]4 years ago
4 0
The height of the tennis ball,relative to the ground is H=h max+h-->h max-the maximum height that the tennis ball reaches relative to the roof of the building; h-the height of the building;h max =v0^2/2g=24,2m(g=10m/s^2).H=gt^2/2=>24,2+h=gt^2/2=>h=gt^2/2-24,2=180,6m
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SashulF [63]
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3 0
3 years ago
A particle has a charge of -4.25 nC.
SpyIntel [72]

Answer:

-611.32 N/C

0.43723 m

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

q = Charge = -4.25 nC

r = Distance from particle = 0.25 m

Electric field is given by

E=\dfrac{kq}{r^2}\\\Rightarrow E=\dfrac{8.99\times 10^9\times -4.25\times 10^{-9}}{0.25^2}\\\Rightarrow E=-611.32\ N/C

The magnitude is 611.32 N/C

The electric field will point straight down as the sign is negative towards the particle.

E=\dfrac{kq}{r^2}\\\Rightarrow r=\sqrt{\dfrac{kq}{E}}\\\Rightarrow r=\sqrt{\dfrac{8.99\times 10^9\times 4.25\times 10^{-9}}{13}}\\\Rightarrow r=1.71436\ m

The distance from the electric field is 1.71436 m

4 0
3 years ago
Read 2 more answers
Sino tao ang gutom?<br>A.you<br>B.mama mo!<br>C.tamod​
Fiesta28 [93]
The answer to that question is c. tamod
5 0
3 years ago
How does the diameter of the disk of milky way galaxy compare to its thickness?
weqwewe [10]
The diameter is about 100 times as great as the thickness.
7 0
4 years ago
A plane has a cruising speed of 250 miles per hour when there is no wind. at this speed, the plane flew 300 miles with the wind
Darina [25.2K]

V = speed of the plane with no wind = 250 mph

v = speed of wind  

consider the motion of the plane while traveling with the wind :

V' = speed of plane travelling in the direction of wind = V + v = 250 + v

d' = distance traveled = 300 miles  

t' = time taken to travel the distance  

time taken to travel the distance is given as  

t' = d'/V'

t' = 300/(250 + v)                                           eq-1

 

consider the motion of the plane while traveling against the wind :

V'' = speed of plane travelling against the direction of wind = V - v = 250 - v

d'' = distance traveled = 200 miles  

t'' = time taken to travel the distance  

time taken to travel the distance is given as  

t'' = d''/V''

t'' = 200/(250 - v)                                           eq-2

Given that :

time taken to travel 300 miles = time taken to travel 200 miles  

t' = t''

using eq-1  and eq-2

300/(250 + v)  = 200/(250 - v)

3/(250 + v)  = 2/(250 - v)

750 - 3 v = 500 + 2 v  

5 v = 250

v = 50 mph

5 0
3 years ago
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