Answer:
Temperature at which molybdenum becomes superconducting is-272.25°C
Explanation:
Conductor are those hard substances which allows path of electric current through them. And super conductors are those hard substances which have resistance against the flow of electric current through them.
As given, molybdenum becomes superconducting at temperatures below 0.90 K.
Temperature in Kelvins can be converted in °C by relation:
T(°C)=273.15-T(K)
Molybdenum becomes superconducting in degrees Celsius.
T(°C)=273.15-0.90= -272.25 °C
Temperature at which molybdenum becomes superconducting is -272.25 °C
This reaction is called a composition reaction.
1s2,2s2.2p6,3s2,3p6,3d4,4s2
Answer: The value of
for the half-cell reaction is 0.222 V.
Explanation:
Equation for solubility equilibrium is as follows.

Its solubility product will be as follows.
![K_{sp} = [Ag^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
Cell reaction for this equation is as follows.

Reduction half-reaction:
, 
Oxidation half-reaction:
,
= ?
Cell reaction: 
So, for this cell reaction the number of moles of electrons transferred are n = 1.
Solubility product, ![K_{sp} = [Ag^{+}][Cl^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BAg%5E%7B%2B%7D%5D%5BCl%5E%7B-%7D%5D)
= 
Therefore, according to the Nernst equation
At equilibrium,
= 0.00 V
Putting the given values into the above formula as follows.

= 
= 0.577 V
Hence, we will calculate the standard cell potential as follows.



= 0.222 V
Thus, we can conclude that value of
for the half-cell reaction is 0.222 V.
Answer:
D. The electron moved up to an energy level and has an energy of 21.72 x 10−19 J.