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Luden [163]
3 years ago
11

When the vessel and its contents are warmed to 100 °C, Q decomposes into its constituent elements. What is the total pressure, a

nd what are the partial pressures of xenon and oxygen in the container?

Engineering
1 answer:
Aleksandr [31]3 years ago
4 0

Answer:

The question is incomplete, but here is a similar question with complete details ; Gaseous compound Q contains only xenon and oxygen . When 0.100 g of Q is placed in a 50.0 mL steel vessel at 0 °C, the pressure is 0.229 atm. (a) What is the molar mass of Q (b) When the vessel and its contents are warmed to 100 °C, Q decomposes into its constituent elements . What is the total pressure , and what are the partial pressures of Xenon and Oxygen

Explanation:

The step by step calculations is as shown in the attached file.

It should be noted that what was applied is

  1. The Ideal gas equation PV = nRT
  2. Daltons law of partial pressure which states that in a mixture of gases, the total pressure exerted is equal to the sum of the individual partial pressures of the gases at constant temperature.
  3. It should be noted that the total pressure of the gases can be gotten by applying pressures law at constant volume
  4. P1/P2 = T1/T2
  5. It should also be noted that Partial pressure = Total pressure x Mole fraction

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Answer:

The percentage volume change is -3.0%

Explanation: We are to determine the percentage change that will occurs is alpha-Mn is transformed to beta-Mn

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Cubic structure (a0) for beta-Mn = 0.6326nm = 0.6326e-9m = 2.5316e-28cm3

Density of alpha-Mn = 7.47g/cm3

Density of beta-Mn = 7.26g/cm3

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STEP1: CALCULATE THE ATOM NUMBER PER CELL IN THE ALPHA-Mn;

Atom per cell = (density × cubic structure × Avogadro's constant) ÷ (atomic weight ) × 100000

(7.47× 7.1236e-28 × 6.02e23) ÷ 54.938 = 58.31

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STEP2: CALCULATE THE NUMBER OF ATOM PER CELL IN THE BETA-Mn

Atom per cell = (density × cubic structure × Avogadro's constant) ÷ (atomic weight) × 1000000

(7.26 × 2.5316e-28 × 6.02e23) ÷ 54.938 = 20.14

Therefore the number of Atom in beta-Mn is 20.14 atom per cell

STEP3: CALCULATE THE PERCENTAGE VOLUME OF ALPHA-Mn AND BETA-Mn

V% = [(volume of atom × number of atom per cell) ÷ volume of unit cell] × 1000

For Alpha-Mn:

[(1.4049e-30 × 58.31) ÷ 7.1236e-28] × 1000 = 114.998%

For Beta-Mn:

[(1.4049e-30 × 20.14) ÷ 2.5316e-28] × 1000 = 111.766%

STEP4: CALCULATE THE CHANGE IN PERCENTAGE VOLUME FOR ALPHA TO TRANSFORM TO BETA

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Therefore;

Change = 111.766 - 114.998 = -3.23%

Therefore for a transformation of Alpha-Mn to Beta-Mn they will be a decrease in volume

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