Answer:
(a) Relative Humidity = 48%,
Specific humidity = 0.0095
(b) Enthalpy = 65 KJ/Kg of dry sir
Specific volume = 0.86 m^3/Kg of dry air
(c/d) 12.78 degree C
(e) Specific volume = 0.86 m^3/Kg of dry air
Answer:
15.8
0.0944
Explanation:
L = 1.5
B = 1.0
Speed of water = 15cm
Temperature = 20⁰C
At 20⁰C
Specific weight = 9790
Kinematic viscosity v = 1.00x10^-4m²/s
Dynamic viscosity u = 1.00x10^-3
Density p = 998kg/m²
Reynolds number
= 0.15x1.5/1.00x10^-4
= 225000
S = 5
5x1.5/225000^1/2
= 0.0158
= 15.8mm
Resistance on one side of plate
F = 0.664x1x1.0x10^-3x0.15x225000^1/2
= 0.04724N
Total resistance
= 2N
= 2x0.04724
= 0.0944N
Answer:
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Explanation:
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Answer:
5.118 m^3/hr
Explanation:
Given data:
viscosity of cell broth = 5cP
cake resistance = 1*1011 cm/g
dry basis per volume of filtrate = 20 g/liter
Diameter = 8m , Length = 12m
vacuum pressure = 80 kpa
cake formation time = 20 s
cycle time = 60 s
<u>Determine the filtration rate in volumes/hr expected fir the rotary vacuum filter</u>
attached below is a detailed solution of the question
Hence The filtration rate in volumes/hr expected for the rotary vacuum filter
V' = ( ) * 1706.0670
= 5118.201 liters ≈ 5.118 m^3/hr