Answer:
V = 0.5 L
Explanation:
Given data:
Moles of nitrogen = 2.23×10⁻² mol (0.0223 mol)
Temperature = 273 K
Pressure = 1 atm
Volume = ?
Solution:
PV = nRT
V = nRT / P
V = 0.0223 mol × 0.0821 atm. mol⁻¹. L . k⁻¹ × 273 K / 1 atm
V = 0.5 L
One atmosphere is equal to 101.3 kilopascals, the measurement of force that the atmosphere exerts at sea level. To convert 112 atmospheres to kilopascals, simply multiply the two together.
112 atm x (101.3 kPa/1 atm) = 11,345.6 kPa
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conversion factor
112 atmospheres is the same amount of pressure as 11,345.6 kilopascals.
