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Oxana [17]
3 years ago
7

Please show the work and steps. The answer is (3.3 s, 15 m/s)

Physics
1 answer:
Anna [14]3 years ago
8 0

Answer:

t = 3.3 s and V = 15 m/s

Explanation:

Given that,

Distance covered by the car, d = 50 m

Initial speed, u = 5 m/s

Final speed, v = 25 m/s

Firstly we can find the acceleration of the car using third equation of motion. i.e.

v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(25)^2-(5)^2}{2(50)}\\\\a=6\ m/s^2

Let t is the time taken by the car to occur this.

t=\dfrac{v-u}{a}\\\\t=\dfrac{25-5}{6}\\\\t=3.3\ s

Let v is the average velocity of the car. It can be calculated as follows :

V=\dfrac{u+v}{2}\\\\V=\dfrac{25+5}{2}\\\\V=\dfrac{30}{2}\\\\V=15\ m/s

So, the time taken by the car to occur this is 3.3 seconds and the average velocity of the car is 15 m/s.

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A cell membrane consists of an inner and outer wall separated by a distance of approximately 10 nm. Assume that the walls act li
ser-zykov [4K]

Answer:

E = 1.1 10⁶ N / C

Explanation:

In this case they indicate that we can approximate the membrane as a parallel plate capacitor, we can use

            E = \frac{\sigma}{\epsilon_o }

note that in this case the electric field created by each plate goes in the same direction, they are added

let's calculate

            E =  \frac{10^{-5}}{8.85 \ 10^{-12}}

            E = 1.1 10⁶ N / C

3 0
3 years ago
A 0.086 kg bullet is fired at 266 m/s and collides with a 6.3 kg wooden block that is initially stationary. The bullet embeds in
olga2289 [7]

Answer:

The value of speed of wooden block at the instant after the collision   V_f = 262.41  \frac{m}{s}

Explanation:

Given data

Mass of block = 6.3 kg

Mass of bullet = 0.086 kg

Velocity of bullet V_0 = 266 \frac{m}{s}

Final velocity of whole system is

V_f = M_{b}\frac{ V_0}{M_b + (M_{block})}

Put all the values in above formula we get

V_f = \frac{(6.3)(266)}{(6.3 + 0.086)}

V_f = 262.41  \frac{m}{s}

This is the value of speed of wooden block at the instant after the collision.

7 0
3 years ago
if a scientist is comparing two different earthquake waves and notices that the amplitude is the same for both, but earthquake 1
olganol [36]
The one with the higher frequency has more energy than the other.
5 0
3 years ago
A rock thrown with speed 7.50 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 18.0 m bef
Iteru [2.4K]

Answer:

height from where rock was thrown is 27.916 m

Explanation:

speed = 7.50 m/s

θ = 30°

g= 9.8 m/s²

horizontal distance = 18 m

time require for vertical displacement

time = \frac{distance}{velocity} \\t = \frac{18}{7.5\ cos30^0}

t = 2.8 sec

now for calculation of height

s = ut + 0.5 a t²

-h = v sinθ× t + 0.5 ×(-9.8)× (2.8²)

-h = 7.5 sin30°× 2.8 - 0.5 ×(9.8)× (2.8²)

-h = -27.916 m

h= 27.916 m

height from where rock was thrown is 27.916 m

5 0
3 years ago
A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min. How far does the car travel whil
Vesna [10]

Explanation:

<u>Using Equations of Motion</u> :

(1) v = u + at

24 = 6.5 + a * 210

<u>a (Acceleration) = 0.083 m/s^2 </u>

<u>(</u><u>2</u><u>)</u><u> </u> v^2 = u^2 + 2aS

S = 576 - 42.25 / 0.166

<u>S (Distance travelled) = 3215.3 m </u>

(Option A seems a typo since the answer is 3215.3 m)

4 0
3 years ago
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