Question

Please show the work and steps. The answer is (3.3 s, 15 m/s)

Answer 1

Answer:

t = 3.3 s and V = 15 m/s

Explanation:

Given that,

Distance covered by the car, d = 50 m

Initial speed, u = 5 m/s

Final speed, v = 25 m/s

Firstly we can find the acceleration of the car using third equation of motion. i.e.

$v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(25)^2-(5)^2}{2(50)}\\\\a=6\ m/s^2$

Let t is the time taken by the car to occur this.

$t=\dfrac{v-u}{a}\\\\t=\dfrac{25-5}{6}\\\\t=3.3\ s$

Let v is the average velocity of the car. It can be calculated as follows :

$V=\dfrac{u+v}{2}\\\\V=\dfrac{25+5}{2}\\\\V=\dfrac{30}{2}\\\\V=15\ m/s$

So, the time taken by the car to occur this is 3.3 seconds and the average velocity of the car is 15 m/s.