The acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².
<h3>How to calculate acceleration?</h3>
The acceleration of a freight train can be calculated using the following formula:
Force = mass × acceleration
According to this question, a 600,000kg freight train can produce 100,000N of force. The acceleration is as follows:
100,000 = 600,000 × a
100,000 = 600,000a
a = 0.167m/s²
Therefore, the acceleration of a 600,000 kg freight train, if each of its three engines can provide 100,000N of force is 0.167m/s².
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The electric field of a very large (essentially infinitely large) plane of charge is given by:
E = σ/(2ε₀)
E is the electric field, σ is the surface charge density, and ε₀ is the electric constant.
To determine σ:
σ = Q/A
Where Q is the total charge of the sheet and A is the sheet's area. The sheet is a square with a side length d, so A = d²:
σ = Q/d²
Make this substitution in the equation for E:
E = Q/(2ε₀d²)
We see that E is inversely proportional to the square of d:
E ∝ 1/d²
The electric field at P has some magnitude E. Now we double the side length of the sheet while keeping the same amount of charge Q distributed over the sheet. By the relationship of E with d, the electric field at P must now have a quarter of its original magnitude:

The approximate lateral area of the prism is determined as 831 square inches.
<h3>
What is lateral area of the hexagonal prism?</h3>
The lateral area of the hexagonal prism is calculated as follows;
LA = PH
where;
- P is perimeter of the prism
- H is height
A = ¹/₂Pa
where;
- a is apothem = 10 inches
- A is base area = 346.41 in²
346.41 = ¹/₂(10)P
346.41 = 5P
P = 346.41/5
P = 69.282 inches
LA = PH
LA = 69.282 x 12
LA = 831.38 in²
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The volume corresponds to the measure of the space occupied by a body. From the given dimensions we can intuit that we are looking to find the Volume of an Cuboid, that is, an orthogonal rectangular prism, whose faces form straight dihedral angles.
Mathematically the volume of this body is given as

Where,
L = Length
W = Width
H = High


Note: The value given for the height was in centimeters, so it was transformed to meters.