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Butoxors [25]
3 years ago
12

Which algebraic expression is a polynomial? 4x2 – 3x + StartFraction 2 Over x EndFraction –6x3 + x2 – StartRoot 5 EndRoot 8x2 +

StartRoot x EndRoot –2x4 + StartFraction 3 Over 2 x EndFraction
Mathematics
2 answers:
rusak2 [61]3 years ago
7 0

Answer:

The Answer is B

Step-by-step explanation:

Veseljchak [2.6K]3 years ago
3 0

Answer:

B.-6x^3+x^2-\sqrt5

Step-by-step explanation:

Polynomial of one variable:It is that expression in which power of each variable in the given should be a whole number.The highest power of variable is called degree of polynomial.

Power of  variable in given terms cannot be negative or fraction.

A.4x^2-3x+\frac{2}{x}

It can be write as

4x^2-3x+2x^{-1}

By definition of polynomial of one variable , it is not a polynomial.

B.-6x^3+x^2-\sqrt5

By definition of polynomial of one variable , it is a  polynomial.

C.8x^2+\sqrt{x}

By definition of polynomial of one variable, it is not  a polynomial.

D.-2x^4+\frac{3}{2x}

By definition of polynomial of one variable,it is not  a polynomial.

Hence, option B is true.

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Answer:

Light

Step-by-step explanation:

He is below the standard deviation limits for average or normal.

5 0
3 years ago
To decrease an amount by 7%, what single multiplier should you use?
notka56 [123]
To decrease an amount by 7%  what single multiplier would you use.  You  want 7% less than 100%, so the answer is (100%-7%)=93% =0.93. Hope I helped! 
4 0
3 years ago
List 3 values that would make this inequality true 3n > 12 a line is supposed to be under it >
Marizza181 [45]

Answer: n≥4

Step-by-step explanation:

If you put the value of 4 as n and multiply it by three you will get twelve which satisfies the inequality. Anything larger than 4 will also satisfy the inequality. I really hope this answer helped tell me in the comments.

3 0
3 years ago
Read 2 more answers
A pendulum clock is a clock that uses a swinging weight (a pendulum) as its
Gnoma [55]

Answer: x(t) = 5cm*cos(t*pi/2s)

Step-by-step explanation:

This is a sinusoidal equation, so we can write this as:

x(t) = A*cos(c*t + p)  + B

where B is the axis around the movement, as the resting position is x = 0, we have B = 0

so x(t) = A*cos(c*t + p)

A is the amplitude of the oscilation, c is the frequency and p is a phase.

We know that when t = 0s, we have x(2s) = 5cm

if this is the maximum displacement, then knowing that the maximum of the cosine is cos(0) = 1

then we must have that p = 0

x(0s) = A*cos(0) = 5cm

then we have A = 5cm

Now, when t = 2s, we have:

x(2s) = 5cm*cos(2s*c) = -5cm

then 2s*c is the minimum of the cos(x) function, this is:

cos(pi) = -1

then 2s*c = pi

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then our function is:

x(t) = 5cm*cos(t*pi/2s)

7 0
2 years ago
What isn’t the answer to this? Someone please help.
Illusion [34]

1/x = 7.5/80

Cross multiply

7.5x=80

Divide by 7.5

10.66

Convert to fraction

10 and 2/3

3 0
3 years ago
Read 2 more answers
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