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scZoUnD [109]
3 years ago
10

Which of the following radiations consists of a helium nucleus emitted by some radioactive substances? Alpha radiation Beta radi

ation Electromagnetic radiation Gamma radiation
Chemistry
1 answer:
erica [24]3 years ago
5 0

Answer: Alpha radiation

Explanation: Alpha decay : When a larger radioactive nuclei decays into smaller nuclei by releasing alpha radiation, the mass number and atomic number is reduced by 4 and 2 units respectively.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}Y+_2^4\textrm{He}


Beta decay : When a larger radioactive nuclei decays into smaller nuclei by releasing beta radiation, the atomic number is increased by 1 unit.


_Z^A\textrm{X}\rightarrow _{Z+1}^{A}Y+_{-1}^0e


Gamma decay : When a larger radioactive nuclei decays into smaller nuclei by releasing gamma radiation, the mass number remains same.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

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For the Earth's atmosphere, section number two in the pie graph BEST represents the percentage of A) argon B) oxygen C) nitrogen
larisa86 [58]

-<u><em>Oxygen</em></u>

According to Google these are the percentages of the <em>Earths Atmosphere</em>

<em>1</em> 78% - Nitrogen

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Write the name of the main gases in the air​
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3 years ago
Read 2 more answers
En un vaso de precipitado de un litro se coloca exactamente 500 mL de agua destilada a temperatura ambiente y se realizan dos ex
Serga [27]

Answer:

1) La masa del agua a temperatura ambiente es de 500 gramos, 2) La masa del agua cuando se congela es de 500 gramos, 3) La masa de agua que queda después de la evaporación es de 400 gramos, 4) Se ha evaporado 100 gramos de agua.

Explanation:

1) <em>¿Cuál es la masa de agua a temperatura ambiente?</em>

Podemos determinar la masa inicial del agua (m_{o}), medido en gramos, al conocer su densidad (\rho_{w}), medida en gramos por mililitro, y volumen inicial ocupado en el vaso de precipitado (V_{o}), medido en mililitros, a partir de la siguiente expresión:

m_{o} =\rho_{w}\cdot V_{o}

Si sabemos que \rho_{w} = 1\,\frac{g}{mL} y V_{o} = 500\,mL, entonces:

m_{o} = \left(1\,\frac{g}{mL} \right)\cdot (500\,mL)

m_{o} = 500\,g

La masa del agua a temperatura ambiente es de 500 gramos.

2) <em>¿Cuál es la masa de agua cuando se congela?</em>

Puesto que el proceso de congelación no implica transferencia de masa, la masa de agua se conserva al transformarse en hielo. Por tanto, la masa resultante es de 500 gramos.

3) <em>¿Cuál es la masa de agua que queda después de la evaporación?</em>

Durante la evaporación una parte del agua es transferida al aire, entonces podemos calcular la masa final (m_{f}), medido en gramos, de la sustancia al multiplicar el volumen final (V_{f}), medido en mililitros, por la densidad del agua (\rho_{w}), medida en gramos por mililitro,. Es decir,

m_{f} =\rho_{w}\cdot V_{f}

Si sabemos que \rho_{w} = 1\,\frac{g}{mL} y V_{f} = 400\,mL, entonces:

m_{f} = \left(1\,\frac{g}{mL} \right)\cdot (400\,mL)

m_{f} = 400\,g

La masa de agua que queda después de la evaporación es de 400 gramos.

4) <em>¿Qué masa de agua se evaporó? </em>

Determinamos que la masa evaporada de agua (m_{v}), medida en gramos, es igual a la diferencia entre las masas inicial y final, ambas medidas en gramos:

m_{v} =m_{o}-m_{f}

Si m_{o} = 500\,g y m_{f} = 400\,g, entonces tenemos que:

m_{v} = 500\,g -400\,g

m_{v} = 100\,g

Se ha evaporado 100 gramos de agua.

5 0
3 years ago
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