To identify why a metal measurement was different in the experiments look for the variable that was different in the experiment and analyze how this change affected the results.
<h3>What is an experiment?</h3>
An experiment is a procedure that aims at probing or discovering something. For example, you can test if a plant grows faster/slower by using an experiment.
<h3>What causes different results in similar experiments?</h3>
The most common cause for this situation is that one of the factors or variables is slightly different. For example, if I add 50mL of water to a plant rather than 20mL of water every day this might cause different results.
Based on this, if the metal content was different you should analyze if any of the factors changed in this experiment and find out how this change affected the general results.
Note: This question is incomplete because there is limited information about the experiment; due to this, I answered it based on general knowledge.
Learn more about experiments in: brainly.com/question/13270830
Something moving. Change in temperature.
Answer:
viscosity
Explanation:
one one left is mercury and the other one is honey right?
"Only electrons are involved in chemical reactions" is the statement among the following choices given in the question that is the <span>best explanation for chemical reactions not to produce radioactive particles. The correct option among all the options that are given in the question is the third option or option "C". </span>
Answer:
carbon dioxide
Explanation:
Carbon burns in oxygen to form carbon dioxide. Since hydrocarbon fuels only contain two elements, we always obtain the same two products when they burn. In the equation below methane (CH 4) is being burned. The oxygen will combine with the carbon and the hydrogen in the methane molecule to produce carbon dioxide (CO 2) and water (H 2O).
Carbon, as graphite, burns to form gaseous carbon (IV) oxide (carbon dioxide), CO2. ... When the air or oxygen supply is restricted, incomplete combustion to carbon monoxide, CO, occurs. 2C(s) + O2(g) → 2CO(g) This reaction is important. When one mole of carbon is exposed to some energy in the presence of one mole of oxygen gas, one mole of carbon dioxide gas is produced. This reaction is a combustion reaction.
