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alina1380 [7]
3 years ago
9

When one atom of sodium (Na) combines with one atom of fluorine (F), they form the compound sodium fluoride (NaF). Which of the

following best describes the arrangement of valence electrons in a bond between Na and F?
The valence electrons are shared equally between Na and F.
The valence electrons spend more time around the atom of Na.
The valence electrons spend more time around the atom of F.
The valence electrons are given up by the Na and gained by the F.
Chemistry
2 answers:
sladkih [1.3K]3 years ago
5 0
The valence electrons spend more time around the atom of F.

Hope this helps!! (If not sorry!)
MArishka [77]3 years ago
3 0
Na is a cation (positive) and F is a anion (negative) this is an ionic bond. In a ionic bond the cation loses its valence electrons to give them to the anion. In this case Na will give its valence electron to F so F can complete its octet:)
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vampirchik [111]

Answer:

The answer to your question is below

Explanation:

Physical properties are the properties in which there is no change in the nature of the substance  but there is a change in the physical state.

Chemical properties are the properties in which the substance changes its nature. A new substance is formed.

A. Ice melts in the sun. Physical p.

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3 years ago
Calculate the speed of a dog running through a field if he is covering 23.7 meters in 54 seconds.
Elenna [48]

Explanation:

speed = distance/time

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3 years ago
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A 110 g copper bowl contains 240 g of water, both at 21.0°C. A very hot 410 g copper cylinder is dropped into the water, causing
vlada-n [284]

Answer:

There is 98.76 kJ energy transfered to the water as heat.

Explanation:

<u>Step 1:</u> Data given

Mass of copper bowl = 110 grams

Mass of water = 240 grams

Temperature of water and copper = 21.0 °C

Mass of the hot copper cylinder = 410 grams

8.6 grams being converted to steam

Final temperature = 100 °C

<u>Step 2:</u> Calculate the energy gained by the water:

Q = m(water)*C(water)*ΔT + m(vapor)*Lw

⇒with mass of water = 0.240 kg

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⇒ with ΔT = the change in temperature = T2 - T1 = 100 °C - 21.0 = 79°C

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⇒ with Lw = The latent heat of vaporization (water to steam) = 22.6 *10^5 J/kg

Q = 0.24kg * 4184 J/kg°C *79°C + 0.0086 kg*22.6*10^5 J/kg

Q = 79328.64 + 19436 = 98764.64 J = 98.76 kJ

There is 98.76 kJ energy transfered to the water as heat.

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