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3 years ago

If the sun is scaled down to 9.5 inches in diameter, the earth would be about _____ inches in diameter

Physics

1 answer:

vovangra [49]3 years ago

7 0

Answer: 0.087 inches

Explanation:

This problem can be solved applying the Rule of three, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known.

In this sense, the actual diameter of the Sun is 1,391,020 km and the actual diameter of the Earth is 12,742 km.

Now, applying the Rule of three:

Sun 1,391,020 km ------ 9.5 inches

Earth 12,742 km --------- ? inches

$? inches=\frac{(12,742 km)(9.5 inches)}{1,391,020 km}$

$? inches=0.087 inches$

Therefore:

If the sun is scaled down to 9.5 inches in diameter, the earth would be about 0.087 inches in diameter.

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MatroZZZ [7]

The average velocity is -4.17 m/s

Explanation:

The average velocity of a body is given by:

$v=\frac{d}{t}$

where

d is the displacement of the body

t is the time elapsed

For the student in this problem, we have:

Initial position: $x_i = 450 m$

Final position: $x_f = 200 m$

So the displacement is

$d=x_f -x_i = 200 - 450 = -250 m$

The time elapsed is

t = 60 s

Therefore, the average velocity is

$v=\frac{-250}{60}=-4.17 m/s$

Where the negative sign means the student is moving towards the origin.

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3 years ago

In the fusion reaction occurring in the Sun, how does the mass of helium atom formed compare to the mass of the hydrogen atoms?

PolarNik [594]

B bc there is a lot of hydrogen used

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3 years ago

Work done by a gravitational force by lowering the bucket into the well is

katovenus [111]

Answer:

when we lower a bucket into a well to fetch water, the work done by gravity is positive since force and displacement are in the same direction.

Explanation:

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3 years ago

a 4m long straight wir that carries acurrent of 0.5A is placed perpendicular to a uniform magnetic field. if the size of magneti

PolarNik [594]

Answer:

B=0.2T

Explanation:

given required solution

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3 years ago

Ted Clubber Lang. A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at t

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Answer:

15 m/s or 1500 cm/s

Explanation:

Given that

Speed of the shoulder, v(h) = 75 cm/s = 0.75 m/s

Distance moved during the hook, d(h) = 5 cm = 0.05 m

Distance moved by the fist, d(f) = 100 cm = 1 m

Average speed of the fist during the hook, v(f) = ? cm/s = m/s

This can be solved by a very simple relation.

d(f) / d(h) = v(f) / v(h)

v(f) = [d(f) * v(h)] / d(h)

v(f) = (1 * 0.75) / 0.05

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v(f) = 15 m/s

Therefore, the average speed of the fist during the hook is 15 m/s or 1500 cm/s

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3 years ago