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Tema [17]
2 years ago
5

A changing climate has strong implications for biodiversity. Studies of fossil and pollen distribution show that species are ver

y sensitive to climate changes. When the climate changes, species often die out in their present areas and colonize new areas. Therefore, as the climate changes in the future, there will be disruption of natural communities and extinction of populations and species.
Based on the information above, which of these would most likely be affected by a global warming?
A) Rattlesnakes in the desert.
B) Polar bears living on the sea ice.
C) Earthworms burrowing in the ground.
D) Spider monkeys in the tropical rain forests.
Physics
2 answers:
Eva8 [605]2 years ago
6 0

Answer: B) Polar bears living on the sea ice.  

Global warming is a natural phenomena which involves the increase in the global atmospheric temperatures because of the human activities such as deforestation, burning of the fossil fuels and others. Terrestrial as well as aquatic animals and other life forms are directly or indirectly are affected by global warming. Global warming is related with the melting of the global glaciers.

The polar bear is a species of bear which is a native of Arctic glacier region. These animals are adapted to survive in the harsh winter conditions of the Arctic region. The change in the climatic conditions in the Arctic region due to global warming will directly influence the population of these animals in a negative sense. These organisms have thick coat and consists of heavy body fat, they cannot survive in hot summer conditions.

ivolga24 [154]2 years ago
4 0
The answer is B i believe.
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7nadin3 [17]
It has to due with numbers so I would say the last one!
5 0
3 years ago
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As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted o
astraxan [27]

Answer:

3.6 x 10⁶ Pa

Explanation:

A = Area of the heel = 1.50 cm² = 1.50 x 10⁻⁴ m²

m = mass of the woman = 55.0 kg

g = acceleration due to gravity = 9.8 m/s²

Force of gravity on the heel is given as

F = mg

Inserting the values

F = (55) (9.8)

F = 539 N

Pressure exerted on the floor is given as

P = \frac{F}{A}

P = \frac{539}{1.5\times 10^{-4}}

P = 3.6 x 10⁶ Pa

6 0
3 years ago
A 6.0 kg bucket of water is raised from a well by a rope. if the upward acceleration of the bucket is 3.9 m/s2, find the force e
shutvik [7]
I'm not good with math but I think it is 23.4
8 0
3 years ago
A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m. If her pisto
lapo4ka [179]

Answer:

The diameter of the piston of the players equals 55.136 cm.

Explanation:

from the principle of transmission of pressure in a hydraulic lift  we have

\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{1}}

Since the force in the question is the weight of the individuals thus upon putting the values in the above equation we get

\frac{57.0\times 9.81}{\frac{\pi \times (19.0)^{2}}{4}}=\frac{4\times 120\times 9.81}{\frac{\pi \times D_{2}^{2}}{4}}

Solving for D_{2} we get

D_{2}^{2}=\frac{4\times 120}{57}\times 19^{2}\\\\\therefore D_{2}=\sqrt{\frac{4\times 120}{57}}\times 19\\\\D_{2}=55.136cm

5 0
3 years ago
In tae-kwon-do, a hand is slammed down onto a target at a speed of 10 m/s and comes to a stop during the 7.0 ms collision. Assum
wlad13 [49]

Answer:

(A) Impulse = 9Ns

(B) F = 1286N

Explanation:

Impulse = change in momentum = m(v-u)

v = 0 (the hand comes to a stop)

u = -10m/s

Mass = 0.9kg

Impulse = 0.9 ×(0- (-10))

= 9Ns

(B) F×t = Impulse

F = Impulse/ t

t = 7ms = 7×10-³

F = 9/ (7×10-³)

F = 1286N.

5 0
2 years ago
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